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Tue 5 Jun, 2012 08:39 am
1.) A researcher analyzed the results of an experiment and found that the calculated t-value (on a t-test of independent means) was 1.29, with a total of 15 patients in group A and 14 patients in group B. You have decided on a significance level ≤ .05. Use the table of critical values, and explain why the null hypothesis can or cannot be rejected.
@tmt2114,
The degrees of freedom in a two-sample t-test is n1+n2-2, or 15+14-2=27. Using a table of critical values for t and alpha = 0.05, determine whether your t-score of 1.29 is above or below the critical value for a test done with 27 df. If your observed t value is higher than the critical value then reject the null hypothesis of no difference. If it's less then do not reject the null. The test of independent means is, by nature, a two-sided test which is why you want to use the alpha=0.05 column rather than the 0.025 column. Here's a link to a critical value table.
http://www.ruf.rice.edu/~bioslabs/tools/stats/ttable.html