Statistics - Mega Millions Math - Help!

The same is a little different.

The first pair of pocket aces is about 4/52*3/51 (using a simplified model--single player) or 1 out of 221.

The same pair of aces is the 2*2/52*1/51 (using the same simplified model) 0r 1 out of 663

Assumming random shuffles after each deal the equal number of shuffles then would be

(1/221)*(1/663)^(n-1)=q/(175711536)
where n is the number of deals

Caveat a 9 player game of texas holdem would have different odds.

Rap

I don't think he's saying the same pair of aces every time; he's saying any pair of aces.


So if the odds of getting pocket aces is 1/221, then the odds of doing it twice in a row would be 1/48841, the odds of doing it three times in a row would be 1/10,793,861, etc.