34
   

The worlds first riddle!

 
 
markr
 
  1  
Reply Tue 12 Oct, 2004 09:16 am
16. 0 (missing information)

17. working on this

18. 216

19. working on this

20. working on this
0 Replies
 
Tryagain
 
  1  
Reply Tue 12 Oct, 2004 09:56 am
0 Replies
 
markr
 
  1  
Reply Tue 12 Oct, 2004 10:08 am
16. 0 (missing information)

17. 2

18. 32 (216 was all possible combinations)

19. 2

20. 2*sqrt(5)
0 Replies
 
whimsical
 
  1  
Reply Tue 12 Oct, 2004 11:31 am
Taking a different view... I- 8 + 8 + 8 = I + 8 + HI

Up side down you see this:
IH + 8 + I = 8 + 8 + 8 - I

Changing I's into 1's

1H + 8 + 1 = 8 + 8 + 8 - 1
1H + 9 ..... = ...... 23
14 + 9 ..... = ...... 23

So remove a part of the H to make a 4.


Whim
0 Replies
 
Tryagain
 
  1  
Reply Tue 12 Oct, 2004 11:48 am
0 Replies
 
whimsical
 
  1  
Reply Tue 12 Oct, 2004 11:59 am
16 + 8 = 4.

16 + 8 = 4! add

13- 10 = 13

13 - 0 = 13 remove

whim
0 Replies
 
Tryagain
 
  1  
Reply Wed 13 Oct, 2004 06:42 am
0 Replies
 
whimsical
 
  1  
Reply Wed 13 Oct, 2004 08:02 am
7168 = 75
7+68 = 75

More Aorals:

X - V = V - V
XXX - IL = L + L / - L
LXIV = IIIII / X
0 Replies
 
markr
 
  1  
Reply Wed 13 Oct, 2004 08:58 am
CORRIDORS
Are the corridors closed at the far ends? Is this about catching him before he escapes an open system, or about avoiding an endless search in a closed system? Do we know how much of a head start the criminal got?

COINS
Hnny

AORALS
X-V=V-V
X-V=V=V
0 Replies
 
Tryagain
 
  1  
Reply Wed 13 Oct, 2004 10:35 am
Mark asks, "Have you got a spare $5 Bucks buddy?"
No, wait. That might not have been him; it had more of a southern twang about it. Razz

However Mark did say:

"Are the corridors closed at the far ends?"

A. They sure are.

"Is this about catching him before he escapes an open system"

A. Nope.

"about avoiding an endless search in a closed system?"

A. Yep.

"Do we know how much of a head start the criminal got?"

A. We sure do, about as long as it would take me to get from here to there. However, not more than two days. Give up now, save your sanity.

HINT. If the corridors are to long, there could be a problem.

Whim,
7168 = 75
7+68 = 75 Very Happy

Easy peasy.

Quickies:

If it takes two men three hours to dig a hole, how long does it take four men to dig half a hole Question


A cowboy rode into town on Friday, and rode out again two days later, on Sunday. How could he do this Question

A woman had two sons who were born in the same hour of the same day in the same year, but they were not twins. How could this be Question
0 Replies
 
whimsical
 
  1  
Reply Wed 13 Oct, 2004 12:37 pm
AORALS
X-V=V-V
X-V=V=V Smile
0 Replies
 
markr
 
  1  
Reply Wed 13 Oct, 2004 01:02 pm
DIGGING
No such thing as half a hole.

COWBOY
Well, Sunday is two days after Friday; so he didn't have to resort to riding horses named Friday and Sunday.

SONS
There was a third child. They were triplets.
0 Replies
 
markr
 
  1  
Reply Wed 13 Oct, 2004 02:17 pm
CORRIDORS
I think the cop can catch the thief if the corridors are no longer than 6 meters.
Here's the algorithm. It assumes the thief's luck lasts as long as possible.
Run to the end of corridor A, and come back to the room.
The thief must now be in corridor B or C.
Go 1 meter into corridor B, and come back to the room and light corridors A and C.
Go 2 meters into corridor C, and come back to the room and light corridors A and B.
Go 3 meters into corridor B, and come back to the room and light corridors A and C.
Continue this until the thief is caught.

If the corridors are 6 meters long, the thief remains free the longest if he is at the end of corridor C. When the cop goes from C4 to B5 to the room (14 meters), the thief goes from C6 to A1 (7 meters) and is caught when the cop lights corridor A.

However, if the corridors are 7 meters long, the thief can sneak into corridor A. When the cop goes from B5 to C6 to the room (17 meters), the thief goes from B7 to A1.5 (1.5 meters into A).
0 Replies
 
whimsical
 
  1  
Reply Thu 14 Oct, 2004 05:07 am
Aorals:

0 = 1

01 = 1


whim
0 Replies
 
Tryagain
 
  1  
Reply Thu 14 Oct, 2004 05:40 am
Mark, I think your answer is very well thought out. Cool

I saw it this way. The cop can walk one of the corridors to the end and ensure that the bum is not there. Now he has two corridors - A and B - and he knows that the bum is farther than a0=1 in A and farther than b0=1 in B. The cop runs x0=b0+1=2 meters into A and back in x0 seconds. Now a1 = (x0+1) - x0/2 = x0/2 + 1 = 2 (the cop inspected x0+1 meters of the corridor A, but in x0/2 seconds that he ran back, the bum could reclaim x0/2 meters).

In the corridor B, the bum could make it to the room in b seconds and run into the "clean" corridor for another 1 meter, but the cop is already in the room and he will see the bum, so he can be sure that the bum is still in B, so b1=1. Next, the cop runs x1=a1+1=3 meters into B and back in x1 seconds. Now b2 = x1/2 + 1 = 5/2 and a2 = 1. Thus xn+1 = an+1 + 1 = (xn/2 + 1) + 1 = xn/2 + 2 which converges to 4, thus the maximum corridor length is 5(ish)

Who said they were easy?
DIGGING
No such thing as half a hole. Laughing

COWBOY
Well, Sunday is two days after Friday; so he didn't have to resort to riding horses named Friday and Sunday. Laughing

SONS
There was a third child. They were triplets. Laughing

Whim
Aorals:

0 = 1

01 = 1 Cool

You either get it in a nanosecond or look at it for ages.


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How many stamps will Jason need to buy this time Question



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0 Replies
 
markr
 
  1  
Reply Thu 14 Oct, 2004 08:49 am
Cindy
It is Jan 1 and her birthday is Dec 31. On Dec 30, she was 17. She turned 18 yesterday (Dec 31). She will turn 19 at the end of this year and 20 at the end of next year.

DEAF
He must have heard where she wanted to go.

LIQUID
The liquid didn't dissolve the bottle.

STAMPS
12

SHEEP
3
0 Replies
 
Tryagain
 
  1  
Reply Fri 15 Oct, 2004 01:55 am
Another day, and guess what. Yes, Mark has done it again, a full house. Cool

Cindy Very Happy
It is Jan 1 and her birthday is Dec 31. On Dec 30, she was 17. She turned 18 yesterday (Dec 31). She will turn 19 at the end of this year and 20 at the end of next year.

DEAF Very Happy
He must have heard where she wanted to go.

LIQUID Very Happy
The liquid didn't dissolve the bottle.

STAMPS Very Happy
12

SHEEP Very Happy
3


However to put an end to his winning streak, I propose the following:


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0 Replies
 
markr
 
  1  
Reply Fri 15 Oct, 2004 08:52 am
JAM
Count the pits.

TRAIN
No smoke.

WINDOW
The shards were outside.

PICNIC
7

HORNBEEPER
Did he see a white bear or a penguin?
0 Replies
 
Tryagain
 
  1  
Reply Fri 15 Oct, 2004 12:18 pm
0 Replies
 
whimsical
 
  1  
Reply Fri 15 Oct, 2004 03:46 pm
Quote:
Now, Whim can come up with a problem that is not easily answered, but not so in my case.


I like to create new puzzles, puzzles that you have not seen before. But I think that anybody who can solve puzzles, can also come-up with new ones. So you can too. Often when one is trying to solve a puzzle one mind is getting strange ideas as how to solve it. It's those hairbrained ideas that can be turned into a new puzzle.

Once a new puzzle is presented, we should persue to create more of them.

whim
0 Replies
 
 

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