34
   

The worlds first riddle!

 
 
markr
 
  1  
Reply Mon 12 Jun, 2006 07:25 pm
[size=8]COFFEE
One cup of each.

I couldn't actually do this experiment because I don't like coffee.
[/size]
0 Replies
 
Tryagain
 
  1  
Reply Tue 13 Jun, 2006 12:23 pm
0 Replies
 
markr
 
  1  
Reply Tue 13 Jun, 2006 01:12 pm
[size=8]I don't mind tea, but I rarely drink it.

endive

This sentence has 22 letters.
This sentence has ten letters. (different letters)
This sentence has eleven letters. (again, different letters)
This sentence has twelve letters. (again, different letters)
[/size]
0 Replies
 
Tryagain
 
  1  
Reply Wed 14 Jun, 2006 10:35 am
0 Replies
 
markr
 
  1  
Reply Wed 14 Jun, 2006 01:18 pm
[size=8]nothing
?
sound?
?
in alphabetical order
[/size]
0 Replies
 
whimsical
 
  1  
Reply Thu 15 Jun, 2006 02:02 am
You have a farm a need to buy three sorts of animals

Horse cost 10 dollar
Goat cost 2.5 dollar
chicken cost 0.10 dollar

Normally you have 100 dollar and nee d to buy 100 animals total, but here is the twist, it is possible to solve the puzzle for x dollar and x animals, but what is the minimal whole number of dollars for x to solve this puzzle?
0 Replies
 
markr
 
  1  
Reply Thu 15 Jun, 2006 09:26 am
zero (probably not what you're looking for)

If you don't have to buy at least one of each type of animal, then you can buy 3 goats and 5 chickens for $8.
0 Replies
 
whimsical
 
  1  
Reply Thu 15 Jun, 2006 01:14 pm
But you do need to buy atleast one of each.
0 Replies
 
Tryagain
 
  1  
Reply Thu 15 Jun, 2006 04:27 pm
0 Replies
 
whimsical
 
  1  
Reply Thu 15 Jun, 2006 05:14 pm
Quote:
Hi Whim, long time no see, I hope you are well.
In answer to your riddle, I would say : $13


I well Try, Thanks.

If 13 is the minimum answer you need to buy 13 animals for $13
0 Replies
 
markr
 
  1  
Reply Thu 15 Jun, 2006 07:58 pm
Well, in that case...
1 horse, 3 goats, and 15 chickens for a total of 19 animals.
0 Replies
 
markr
 
  1  
Reply Thu 15 Jun, 2006 09:29 pm
[size=8]AABBCCDDEE
(a) 9!/(2!)^4
or 22680
(b) 10!/(2!)^5 - (a)
or 9!/(2!)^4 * 8/2!
or 90720
(c) C(7,2) * 4!/(2!)^2 * 6!/(2!)^2
or 11340
[/size]
0 Replies
 
whimsical
 
  1  
Reply Fri 16 Jun, 2006 12:18 pm
That's right Mark. I wonder how many possible solutions this puzzle has without the constraint minimum, but with a maximum of 100 animals for $100


19 animals for $19
.
.
.
.
.
100 animals for $100
0 Replies
 
markr
 
  1  
Reply Fri 16 Jun, 2006 02:28 pm
Each horse requires ten chickens to average $1 per animal.
Three goats require five chickens to average $1 per animal.

Therefore, I suspect all solutions are of the form:
11x + 8y
where x and y are positive integers.
0 Replies
 
Tryagain
 
  1  
Reply Fri 16 Jun, 2006 04:14 pm
Mark:


AABBCCDDEE
(a) 9!/(2!)^4 Cool
or 22680

(b) 10!/(2!)^5 - (a) Cool
or 9!/(2!)^4 * 8/2! Cool
or 90720

(c) C(7,2) * 4!/(2!)^2 * 6!/(2!)^2 Cool
or 11340

Is he great or what! Razz



Shari and Pamela are among 10 different women standing in line to enter a theatre. There are exactly 2 people between Shari and Pamela. In how many ways can such a line-up occur Question


Generalize your solution to the problem above for Shari and Pamela being among n different women standing in line to enter a theatre, with exactly k people between Shari and Pamela Question



ACACBSEOLSUSTIEBLLYE


AFCTIIGHOTN
0 Replies
 
markr
 
  1  
Reply Fri 16 Jun, 2006 10:19 pm
[size=8]THEATRE LINE
564,480
2*(n-k-1)*(n-2)!

absolutely inaccessible
fighting action
[/size]
0 Replies
 
Tryagain
 
  1  
Reply Sat 17 Jun, 2006 04:47 pm
Mark:

THEATRE LINE
564,480
2*(n-k-1)*(n-2)! Cool

Or as I saw it 2 * 7 * 8! (same difference) Laughing
Shari (S) and Pamela (P), together with the two people between them, make up a fixed unit. With the four people fixed through this requirement, there are six others to account for, or a total of 7 "spots" in the line-up.

First, choose one of the seven spots for the 4-person unit. This can be done in 7 ways. Now, using the six other spots and the two between S and P, permute the 8 other people into these 8 spots. This can be done in 8! ways. Finally, recognize that P and S could change places, thus there are two ways for S and P to arrange each other within the four-person unit. If you don't believe me, just ask Mark.


absolutely inaccessible Cool
fighting action Cool




Alive without breath,
As cold as death;
Never thirsty, ever drinking,
All in mail never clinking.
Question

This thing all things devours:
Birds, beasts, trees, flowers;
Gnaws iron, bites steel;
Grinds hard stones to meal;
Slays king, ruins town
And beats high mountain down.
Question


Thirty white horses on a red hill,
First they champ,
Then they stamp,
Then they stand still.
Question


No legs lay on one-leg, two-legs sat near on three-legs, four legs got some. Question


A box without hinges, key, or lid,
Yet golden treasure inside is hid.
Question
0 Replies
 
Tryagain
 
  1  
Reply Sun 18 Jun, 2006 02:51 pm
What was the President's name in 1969 Question



A group of campers have been on vacation so long, that they have forgotten the day of the week. The following conversation ensues.

Darryl: What's the day? I don't think it is Thursday, Friday or Saturday.
Tracy: Well that doesn't narrow it down much. Yesterday was Sunday.
Melissa: Yesterday wasn't Sunday, tomorrow is Sunday.
Ben: The day after tomorrow is Saturday.
Adrienne: The day before yesterday was Thursday.
Susie: Tomorrow is Saturday.
David: I know that the day after tomorrow is not Friday.

If only one person's statement is true, what day of the week is it Question
0 Replies
 
whimsical
 
  1  
Reply Sun 18 Jun, 2006 05:03 pm
Code:A B C D E F G H I J
9 3 8 7 8 9 2 8 5 7
1 2 1 5 ? 7 1 0 1 2
K L M N O P Q R S T


What is the missing number and why?
0 Replies
 
whimsical
 
  1  
Reply Sun 18 Jun, 2006 05:05 pm
Quote:
This thing all things devours:
Birds, beasts, trees, flowers;
Gnaws iron, bites steel;
Grinds hard stones to meal;
Slays king, ruins town
And beats high mountain down.


Time
0 Replies
 
 

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