P(none of 1 or5) is 3C0*(2/6)^0* (4/6)^3 = 64/216
P(exactly one of 1 or 5) is 3C1*(2/6)^1*(4/6)^2=96/216
P(exactly two of 1 or 5) is 3C2*(2/6^2*(4/6)^1=48/216
P(exactly three of 1 or 5) is 3C3*(2/6)^3*(4/6)0=8/216
ergo 144/216 , funny how the probabilities add to 1
All that work and you still got it wrong.
0 Replies
oolongteasup
1
Reply
Wed 11 Mar, 2009 08:38 pm
@DrewDad,
my mistake
8 ways to roll all 1's and 5's only 2 of which are all1's or 5's
so 150/216 is correct
0 Replies
maze1on1
1
Reply
Thu 7 Jan, 2016 05:15 pm
@joefromchicago,
For 1 dice: 2/6 or 33%
For 2 dice:20/36 or 55.5%
For 3 dice:152/216 or 70.4%
