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THE MISSING COIN

 
 
Reply Sun 20 Jan, 2008 01:02 pm
three men go to a restaurant to have dinner. the owner of that restaurant comes up to the three men and offers then to eat as much food as they like for only 30 $. the three men share the cost and agree to pay 10$ each to the owner. when the owner goes back to his office, he realizes that today had a special and that the three man could eat as much as they liked for only 25$. And so the honest owner gives 5 $ to the server so he could give that many back to the men. The server didn't know how he could divide 5$ into three equal parts. So the server decides to keep 2$ for himself and gives 1$ to each of the three men. the three man had initially paid 10$ and now received 1$ back as if they had only paid 9$ each. 9$ times 3 men equals 27$, plus the 2 dollars that the sever kept equals 29$. After all, where did that 1 missing dollar go???
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Type: Discussion • Score: 0 • Views: 1,777 • Replies: 3
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Ragman
 
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Reply Sun 20 Jan, 2008 01:07 pm
taxman
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Shapeless
 
  1  
Reply Sun 20 Jan, 2008 01:58 pm
Re: THE MISSING COIN
mars90000000 wrote:
plus the 2 dollars that the sever kept equals 29$.


The $2 that the server kept is already included in the $27 that the three men paid, so there's no reason to add another $2 in order to account for what the server kept.
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TTH
 
  1  
Reply Sun 20 Jan, 2008 02:09 pm
Here are answers:
http://www.able2know.org/forums/viewtopic.php?p=2501832#2501832
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