1
   

A Cow is tied to a barn...

 
 
TTH
 
  1  
Reply Sat 27 Oct, 2007 10:47 am
Is the poor pathetic cow tied inside or outside the barn Laughing Laughing Laughing

Nevermind, I really don't want to know Laughing
0 Replies
 
Bohne
 
  1  
Reply Sun 28 Oct, 2007 03:32 pm
[quote="TTH"]Is the poor pathetic cow tied inside or outside the barn Laughing Laughing Laughing

Nevermind, I really don't want to know Laughing[/quote]

Your questions just show, you have no interest in solving the problem...

Rolling Eyes

:wink:
0 Replies
 
TTH
 
  1  
Reply Sun 28 Oct, 2007 03:35 pm
Bohne wrote:
Your questions just show, you have no interest in solving the problem...

Rolling Eyes

:wink:
You are 100% correct Very Happy
0 Replies
 
TehMeh
 
  1  
Reply Mon 29 Oct, 2007 07:49 pm
markr wrote:
TehMeh wrote:
Can you explain in-depth how you got the second part?

A diagram would be helpful Laughing


I had:
the corners of the barn at:
(0,0), (0,10), (20,0), (20,10)
and the cow tethered at (0,10)

I computed the intersection of these circles:
x^2 + y^2 = 90^2
(x-20)^2 + (y-10)^2 = 80^2

Then it's a matter of computing the angles for the sectors of the circles of radius 90 and 80. Throw in the areas of the two triangles (20, 90, L and 10, 80, L) and you're done.


Why is it 90^2 though? Wouldn't the radius be 100 because of the length of the rope?
0 Replies
 
markr
 
  1  
Reply Mon 29 Oct, 2007 10:24 pm
100 is used for the 3/4 circle.

When the rope turns around a corner, the radius of the circle is diminished by the length of the wall, and the smaller circle is centered at the corner.

90 (100-10) is used for one of the sectors.
80 (100-20) is used for the other sector.
0 Replies
 
TehMeh
 
  1  
Reply Tue 30 Oct, 2007 03:42 pm
I'm a bit at a loss. So from my (crappily drawn in mspaint) diagram, what would you do?

http://img142.imageshack.us/img142/2386/cowji7.th.png
0 Replies
 
markr
 
  1  
Reply Tue 30 Oct, 2007 11:25 pm
Draw a circle of radius 90 centered at the bottom left corner of the rectangle.
Draw a circle of radius 80 centered at the top right corner of the square.
Figure out where (below and to the right of the rectangle) they intersect.
Draw lines from that point to each of the centers of the circles.
That leaves you with two sectors and a concave quadrilateral to compute the areas of.
Break up the quadrilateral into two triangles.
Compute the angles of the sectors.
0 Replies
 
TehMeh
 
  1  
Reply Thu 1 Nov, 2007 06:30 pm
I actually got it by myself miracuclously (before your post)... but your tips basically helped me through it.

Thanks so much Very Happy
0 Replies
 
Doowop
 
  1  
Reply Fri 2 Nov, 2007 04:57 am
Part 1.

If the cow is tethered to the inside of the barn, and who's to say she's not, she will be able to graze up to 100 square feet, provided that the barn exits are all closed and that there is grazing material spread onto all of the floor.
If one or more "cow sized" exits are open, however, or the grazing material is only spread over a portion of the floor, then who knows how much of an area she could possibly chomp? Very Happy
0 Replies
 
 

Related Topics

Alternative Einstein's riddle answer - Discussion by cedor
Urgent !!! Puzzle / Riddle...Plz helpp - Question by zuzusheryl
Bottle - Question by Megha
"The World's Hardest Riddle" - Discussion by maxlovesmarie
Hard Riddle - Question by retsgned
Riddle Time - Question by Teddy Isaiah
riddle me this (easy) - Question by gree012
Riddle - Question by georgio7
Trick Question I think! - Question by sophocles
Answer my riddle - Question by DanDMan52
 
Copyright © 2024 MadLab, LLC :: Terms of Service :: Privacy Policy :: Page generated in 0.06 seconds on 05/18/2024 at 02:52:02