TehMeh wrote:Can you explain in-depth how you got the second part?
A diagram would be helpful
I had:
the corners of the barn at:
(0,0), (0,10), (20,0), (20,10)
and the cow tethered at (0,10)
I computed the intersection of these circles:
x^2 + y^2 = 90^2
(x-20)^2 + (y-10)^2 = 80^2
Then it's a matter of computing the angles for the sectors of the circles of radius 90 and 80. Throw in the areas of the two triangles (20, 90, L and 10, 80, L) and you're done.