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Mon 21 Jul, 2003 12:38 am
usually i have no truble in solving such a thing but for some starnge reason, i cant figure this one out:
60, 55, 51, 27, ??
anyone?
thnx in advance
Shanor.
Hmmm.
60, 55, 51, 27, ??
To get from 60 to 55, you subtract 5. To get to 51, you subtract 4. To get to 27, you subtract 24 (or, 4 times 6). I wonder if it's at all significant that 51, 60 and 27 are all divisible by 3 (27 is a cube).
60 is 3 times 20. 51 is 3 times 17. 27 is 3 times 9.
Shanor posted this 3 weeks ago, it is his/her only posting, which makes me suspicious, I doubt the veracity of this riddle, or to put it in yorkshire terms I think it is a p**s take.