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Mon 26 Mar, 2007 04:43 pm
My insurance company forced me to take a new type of medical examination involving my DNA. With the recent completion of the Human Genome Project, scientists are SURE they can read your life through your DNA.
However, when the results from my test came in, my boss "regretfully" informed me that they had to let me go. He didn't know what was wrong with me, he only told me that my DNA was unusually wide, meaning that the length of one turn of my DNA was longer than that of most humans. The doctors are almost positive that this will have a negative effect on my lifespan. My boss knows nothing of the length of my DNA. The only thing my boss told me was that the formula he used to determine this was:
r(t) = b·cos(t)·i + b·sin(t)·j + (1-b2)1/2·t·k
Can you help me find the length of one turn of my DNA?
Re: Lifespan
official wrote:
Can you help me find the length of one turn of my DNA?
I could; but, this (along with your questions on time and vibrations etc.) sound suspiciously like homework assignments...so I won't do anything to endanger your opportunity of learning on your own by
working a problem through.
It's not homework. If it was, I would simply have said so, or known how to do it.
Posted in the Trivia forum, your questions would probably arouse some interest. Posted in Science & Math they look a lot like homework.
Why not use the "Report" button to ask the moderators to move your threads to the proper forum?
r(t) = b.cos(t).i + b.sin(t).j + (1-b^2)^(1/2).t.k
r is the length
t is the time
b is a constant value
(i,j,k) is the base
Hmm, this is the new one to be worked out for me I guess lol
I get 2*pi.
It's a spiral of radius b.
The height after one revolution (t = 2*pi) is 2*pi*sqrt(1-b^2).
Unroll the spiral to create a triangle.
The base is 2*pi*b. The height was given above.
Now apply Pythagoras to get the hypotenuse, which is the length of one rotation.
Got it
thanks for your help!!! You are the best!