PHP help

Forums: Web Development, Php
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Hey there.

I'm having a difficulty with a php mysql script.

I need a page which shows only 6 pictures.
The adresses of the images are stored in a database.

let's say I have 10 images.
I want the first page to link to a new page with the remaining four images.

first page:
[image] [image] [image]
[image] [image] [image]
next

second page:
[image] [image] [image]
First page:
| include 'table.txt' | | include 'table.txt' | | include 'table.txt' |
| include 'table.txt' | | include 'no.txt' | | include 'no.txt' |
[image]
previous

Here is the code I got from another forum:

Code:

<?php

mysql_connect( "localhost", "username", "password" ); // Use correct stuff there

mysql_select_db( "images" ); // Use Database Name

$max_images = 8;

if( !isset( $_GET[ 'page' ] ) ) {

$page = 1;

}

else {

$page = $_GET[ 'page' ];

}

$from = ($page * $max_images) - $max_images;



// select the image url's from the db, i_id = the id of the row in the mysql db

$sql = "SELECT * FROM images ORDER BY i_id LIMIT $from, $max_images";

$s = mysql_query( $sql );

while( $res = mysql_fetch_array( $s ) ) {

$i = 1;

//example variables, might be different for you



// assuming the row name is "src"

$src = $res[ 'src' ];



echo '<img> ';

if( $i > 4 ) {

 echo '<br>';

}

$i++;

}

echo '<br>';

$total_images = mysql_result( mysql_query( "SELECT COUNT( i_id ) as Num FROM images" ), 0 );

$total_pages = ceil( $total_images / $max_images );

// previous page

if($page > 1){

 $prev = ( $page - 1 );

   echo '<a>Previous</a> ';

}



for( $i = 1; $i <= $total_pages; $i++ ) {

if( ( $page ) == $i ) {  

 echo "$i ";

}

else {

 echo '<a>$i</a> ';

}

}

// next page

if( $page </a>

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