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solid problem while driving

 
 
Reply Mon 13 Mar, 2006 01:53 pm
You traced the target computer across the globe. You finally end up with two coordinates.
One lies at [80 00 00 N 007 45 00 E] and the other at [70 00 00 S 007 45 00 E].
While you plan your next attack, you suddenly get curious... and want these questions answered:

1. How far away are these two towns from each other?
2. If a car drives 200 km/h, how long will it take you to drive from one town to the other?



Just full numbers. (e.g. 12, 104, 1006)

Distance in km:
Drive time in hours:


Somebody please help me with some hints if anybody has done it!! Very Happy
im really stuck on this one!!!!! this one is really SOLID[/b]! hehehehehe!
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Type: Discussion • Score: 1 • Views: 3,198 • Replies: 9
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Tryagain
 
  1  
Reply Mon 13 Mar, 2006 03:07 pm
Hi General, welcome to A2K and the forum. What a start! Cool

If the approximation that the Earth is spherical is made, it is fairly easy to give a general answer to 1. Although I doubt everyone would agree.

Let r_A and r_B be the position vectors of towns A and B with respect
to the centre of the Earth, and let R be the radius of the Earth. Then
d, the distance between A and B is given by d = R*a,

where a is the angle (in radians) between vectors r_A and r_B. This is just the definition of angle.

If you want to use degrees for angle a,

d = R*a*pi/180.

Now, how is the angle a found?

r_A dot r_B = R^2 * cos(a),

so,

a = arccos{(r_A dot r_B)/R^2}

What about r_A dot r_B ?


Code:
r_A dot r_B = x_A * x_B + y_A * y_B + z_A * z_B

= R^2 * [sin(t_A)*cos(p_A)*sin(t_B)*cos(p_B)

+ sin(t_A)*sin(p_A)*sin(t_B)*sin(p_B)

+ cos(t_A)*cos(t_B)]



Latitude and longitude relate directly to spherical coordinates
theta = t and phi = p. Longitude is p (take west to be negative) and
t = 90 - latitude (take south to be negative).

(I've chosen the convention for phi and theta usually used by physicists, which I think is opposite to the convention usually used by mathematicians.)


As for 2. You would be better off in a plane unless you have an amphibious vehicle.
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general bell
 
  1  
Reply Tue 14 Mar, 2006 01:31 pm
woah!!!!!! il try it to see what i get!! Cheers for the help!! i can hopefuly finally solve this SOLID[/b] riddle
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general bell
 
  1  
Reply Thu 16 Mar, 2006 07:11 am
whoa!! still stuck on it! can u help me a bit more?
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general bell
 
  1  
Reply Thu 16 Mar, 2006 07:21 am
or PM me the answers!!
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Tryagain
 
  1  
Reply Fri 17 Mar, 2006 10:59 am
After reading your "Whoa!!" I deleted my answer.

However, if I remember correctly, I made it:

16666/Km. (But it could be in the range, 16666 to 97)

83hours 20 minutes to drive it.


Good luck!
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general bell
 
  1  
Reply Fri 17 Mar, 2006 02:50 pm
none of them work wiv 83hours 20mins and 16666-16697!
its suppose to be logic! not maths! but if uve got any more answers can u tell them to me so i can try them!! please!!
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Scorpio
 
  1  
Reply Fri 24 Mar, 2006 02:38 pm
Riddle Solved
Hmmm the answer is around 12309 in K/m and 83 hours in drive time, not to hard, 12309 k/m: to get from one point to the other, you'd go directly through the earth, hence solid problem.
Ignoring the impossibility of driving from one point to the other you'd get: Around 83 hours Smile

Hope that helped.

Regards,
Scorpio
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general bell
 
  1  
Reply Sun 11 Mar, 2007 05:08 am
Oh thanks scorpio, that was correct but i figured it out already!!!
So thanks for the help anyway!!
My answer was a bit differnt but it was still correct!!!
I had 12500km and 85 hours!!!
0 Replies
 
markr
 
  1  
Reply Mon 12 Mar, 2007 02:37 pm
Since the longitudes are identical, the angle between the cities is 80+70=150 degrees.

Using Google's earth radius (6378.1 km):
Surface route = 150/360 * 2*pi*6378.1 = 16,697.8 km (circumference of circle)
Tunnel route = 6378.1 * sin(150) / sin(15) = 12,321.5 km (law of sines)
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