UNSOLVABLE RIDDLE?!!!!!!!! Need an Answer

The $2 the host kept has already been accounted for in the $27 for the room.

They came in with $30. The hotel got $25, the host got $2, and they each were left with $1.

you are right, there's two ways of looking at this.

1.) The room is 30. the get a 5 discount. 3 given back evenly and 2 the guy kept for himself. which leaves 27. the room is 27 and each guy pays 9 = 27+2 from the hotel guy = 29

2.) The room is 30. they get a 5 discount. 25+ the guy's 2 =27/3=9 and altogether equals 30.

it's all in how you word it. kinda tricky huh.
If nmath is a natural science like they say, then you should be able to do this in addition, multiplication, subtraction, and division.

I think I remember this problem for as long as I know how to add and subtract :wink:

It can be very confusing, especially if worded just right. I've known some people who haven't been able to understand the correct solution from wrong and truly think it's a real paradox.

Why do you add the $2 (guys tip) to the room cost twice?

They were originally charged 30, then they got $3 back, that's 27. These 27 are: 25 for the room plus 2 for the "tip".... You do not add $2 to $27, it's already in it!

Or second way to look at it:
The room was 25, plus $2 tip = $27. That's it. forget the change.

Think of it this way:
You order take out food, and the bill is $25. You want to give delivery guy $2 tip, but you only have $10 bills. So you give him $30, and ask for $3 change. That's basically what was going on there in the hotel.

Here,

The next night two of the men return to stay again. They both give the hotel host $10 each and go to their room. The Host remembers the discount and go up to the room to return 5 dollars for the discount. Realizing he can make a bigger tip, the host keeps $3 and gives back $2 to the men.

Each Man paid $10 - $1 returned = $9

Together the two men paid $18, and add the $3 kept by the Hotel Host,
And you get $21, There, is the missing dollar.

missing dollar
the correct solution is...
$25 was paid to the hotel owner....
$27dollar paid by 3 men... - $2Stole by the other man... = $25 = paid to the hotel owner... ^_^

missing dollar
you have made mistake on making the solution
they paid $30 to the hotel owner but he gave back $5 so it counts $25...
3 men paid $27 but you add the $2 dollars stole by the other person.. but you should subtract for it leaves $25 same amount as they pay to the hotel owner...

Here are the links to the same riddle.

http://www.able2know.com/forums/viewtopic.php?t=64221&postdays=0&postorder=asc&start=0

or

http://www.able2know.com/forums/viewtopic.php?p=2519907&highlight=brother#2519907

okay i made a diagram, this is bothering me:
man 1- $10 man 2- $10 man 3- $10 = $30 total ,right.
$30 - $5 discount = $25 now the inn keeper takes only $2 and gives back $3 = $28 total , correct? $25+$3=28 yup. and the shopkeeper kept $2 which keeps the total at $30 there is no missing dollar, just a mishap of calculation.

Nope.

$30 - $5 discount = $25 now the inn keeper takes only $2 and gives back $3 = $27 total ($25 for the room, $2 to the innkeeper)

Check it out the room was $30. The original discount was $5. so its $30- 5 which is $25. Since they were 3 the hotle guy stayed with $2 so thats $25 + 2= $27. Then plus the other $3 dollars the guy gave them $27+3= $30

Three Men and the Hotel

The linguist will reword the problem and there is no missing money. The mathematician will apply the appropriate procedures and establish there is no missing money as well. However, this is an existential puzzle and a matter of philosophical perspective.

We begin with 3 men paying $30.00 for a room and being overcharged $5.00. The bellboy refunds the 3 men $3.00 or a $1.00 a piece and keeps $2.00.

By the 3 men receiving $1.00 each, they have effectively paid $9.00 each for the room. That is a fact. That is "out of pocket” money. They don't know they tipped anyone. They don't know the room is $25.00. All they know is so far they have together been "out of pocket" $27.00. For them, the room was only $3.00 less than what they originally paid.

1 If they are given the $2.00 back they have paid $25.00 and no money is missing.

2 By re-arranging the order of descriptive events there is no money missing: $30.00 less the bellboy $2.00; less the $3.00 given to the men equals $25.00.

3 By re-languaging the order of events, there is no money missing.

4 If nothing happens, they are still only "out of pocket" $27.00.

A) However, there are 2 other physical dollars held by the bellboy. The assumption thus far, has been to force a relationship of these $2.00 as being a part of the original equation to be subtracted from the $27.00.

As it is, we can account for only $27.00 held by the men and another $2.00 essentially in a state of limbo held by the bellboy. This state does not establish arithmetic relationship for either the mathematician or the linguist. But it does establish existence, temporarily transcending mathematical axioms and semantic considerations. For together only 29 single dollar bills are in factual states, they simply have not yet been assigned a function.

Until the $2.00 is subtracted the philosopher can ask; where is the other dollar?

The concierge steals it!

$1 was the tip ^^

i am like a ball.if you cut me into two i will be like a cup in which you can put things. who am i?