@maxdancona,
The function is
T1 = T0 √(1 - v^2/c^2)
That equation is derived in the textbooks by Sally in a moving spaceship having a flashlight pointed straight up. Why are we required to use only that situation? If Sally is moving to the right why can't Sally have her flashlight pointed upward and to the left at an angle of 53.13 degrees from the horizontal? If that happens the function is now...
T0 = T1 √(1 - v^2/c^2)
Both equations are equally valid depending on how we set up the situation unless there is some fundamental reason why Sally can't have her flashlight pointed upward and to the left.
Earlier I stated that using the first equation we get...
So 0.8 seconds for Sally = 1 second for John.
Using the second equation we get...
So 1 second for Sally = 0.8 seconds for John.
The response was that there is no contradiction because each observer sees the other observer's clock as running more slowly than their own clock. That is a misunderstanding.
It is not...
0.8 seconds for Sally = 1 second for John according to John. (1st equation)
1 second for Sally = 0.8 seconds for John according to Sally. (1st equation)
That is using the first equation only. It is actually...
0.8 seconds for Sally = 1 second for John according to John. (1st equation)
1 second for Sally = 0.8 seconds for John according to John. (2nd equation)
It should be clear now that there is a contradiction.