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# missing numbers

Sun 13 Feb, 2005 04:01 am
1 = 1
2 = 2
3 = 3
4 = 8
5 = 18
6 = 28
7 = 38
8 =
9 =
10 =
11 =
12 =
13 =
14 =
15 =
16 =
17 =
18 =
19 =
20 =

Whim
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Type: Discussion • Score: 1 • Views: 825 • Replies: 9
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markr

1
Sun 13 Feb, 2005 03:28 pm
1, 2, 3, 8, 18, 28, 38, 88, 188, 288, 388, 888, 1888, 2888, 3888, 8888, 18888, 28888, 38888, 88888

What a romantic sequence!
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alfass21

1
Wed 16 Feb, 2005 05:16 am
very easy
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Community Card

1
Wed 16 Feb, 2005 07:07 am
Why not 1, 2, 3, 8, 18, 28, 38, 88, 1888, 2888, 3888 and 8888 directly ?!

Where is the 188, 288, 388, 888 coming from ?
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markr

1
Wed 16 Feb, 2005 10:57 am
C and D
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Liessa

1
Wed 16 Feb, 2005 01:36 pm
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markr

1
Wed 16 Feb, 2005 03:04 pm
ROMAN-tic (it was an attempt to be clever)
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Community Card

1
Thu 17 Feb, 2005 06:34 am
Hmm, the way I understood it was that you have a series of 4, and then you add to the last number of the series all the previous ones.
So the first one being : 1, 2, 3, 8, the second will have to be 18, 28, 38, 88.
Very good so far, and following the same logic, you move from the second series and proceed normally so it should go like : 1888, 2888, 3888 and 8888. You just add to 18, 28, 38, 88 the last number which is 88 !
So whats the deal with C and D
I mean just so I can understand future riddles at least..
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markr

1
Thu 17 Feb, 2005 11:42 am
C is roman for 100
D is roman for 500
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Community Card

1
Fri 18 Feb, 2005 05:55 am
Aha, thx markr !
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