Probability problem

I suggest
(a) 56/132
(b) 7/11
but am open to correction.

@fresco
Can you describe your solution?

a) There are 66 combinations of 2 eggs, 12x11/2. There are 28 combinations of two eggs where both are boiled. 8x7/2. 28/66.

b) Two ways to do this depending on your geek level. First you could say that if the first egg is boiled, there are 11 eggs left, seven of which are boiled, therefore 7/11. The second way is Bayes Theorem. The probability of both boiled is 28/66, the probability of the first being boiled is 8/12, so find 28/66 divided by 8/12 = 7/11

Thank you! I think that's the right solution.

An ordinary tree diagram works with two branches for first egg, each with two branches for the second egg, probabilities being found by multiplication along the branches.
Pedagogically, it would be a poor question because the answer to b is required for the answer to a.