@willzi8,
I put them in alphabetical order but I can't seem to figure out the answer. D:
I'm pretty sure I have all the correct letters. :/
yeah -- this was pretty easy. figured it out in a few minutes once i realized they were ALL in the neopedia. (just got to the board now.)
it came out while i was on my way home, so i'm pretty slow this week. maybe first 250 since no one has blurted it out yet., but kinda doubt it.
I figued it out but I don't think I made the top 250 =P
idk how i got first 250, but I'm STILL silver...
Ermmm, i can't unscramble it... the answer for #7 is **** **a**, right?
Does it have anything to do wth Valentines? it should, right?
PHEW got it, I hope I was fast enough for a neg xD it's prettttyyyy
@Acorna,
help with the answer for question 5 please D:
what does the unscrambled word/words hacve to do about.. i have so many ansers
@wertyiu102,
its a two word answer I think
@Nooblette,
the answer to question 5. the guy is little! like a little boy. actually this was one of the easier ones... i'm having trouble with question 7 T__T... i feel like i'm skipping over something. oh well i don't think i got top 250
@x3jackie,
question 7? If you beat him, it's because of the masterful tips that he gave you?
@Acorna,
I can't seem to unscramble the code! No unscrambler could help me.
as far as i could see, people who had trouble unscrambling had at least one letter wrong - otherwise, it's pretty easy.
tip: google the exact parts of the question and look for answers in neopedia - if applicable, the answer is mainly the exact title of the neopedia article
@beebzzz,
Got it and it only took about 15 minutes. Better than math for me anyway.
@beebzzz,
hm yeah... who could that be?! lenny? :p... T__T
Round 343 solution:
(one about the big sphere with little spheres inside)
Given:
Big Steel Hollow Sphere with diameter = 41 in.
Thickness of big steel sphere's wall = 0.8 in.
Inside, 50 Small Spheres, diameter = 2 in.
Also inside is water.
Density of steel = 490 lb/ft^3
Density of water = 62.4 lb/ft^3
Find:
Total Weight in lb.
(total weight of 1 big steel sphere, 50 small steel spheres, filler water)
Knowing:
Volume of a sphere = (4/3)*pi*r^3
Density = mass/volume (see units of density given)
so we really need to find the following:
1. lb of inner small spheres
2. lb of outside big steel
3. lb of water
all by determining the volume of the elements in question, then multiplying by appropriate density.
sooo....
1. 50 SMALL SPHERES:
I assumed that they were solid steel. (as noted by others, in this particular case, it doesn't quite matter in the end)
Using our volume of a sphere equation, we need the radius. Radius = half the diameter. so r = 1 in.
density is given in lb/ft^3 NOT anything to do with inches. so convert radius to feet: r = 1/12 ft.
plug into volume equation. Volume of 1 small sphere = 0.002424 ft^3 (note units)
multiply by 50 to account for all small spheres.
multiply by density of steel = total weight of all the little spheres
2. BIG SPHERE:
picture it. it's like a shell. imagine one of those cadbury chocolate filled eggs (but in a sphere shape haha) Imagine the chocolate shell as the steel sphere, and the creme inside as the water. We want to look at the volume of only the steel. To do this, we can imagine it as 2 spheres subtracted from each other. if you have a bigger sphere, with a smaller sphere inside, if you subtract the space the small sphere takes up from the bigger sphere, then you get the space IN BETWEEN the two. so that's what you do in this case, by utilizing the 0.8 in. thickness given.
so outside diameter = 41 in.
inner diameter = 41-(0.8)*2 in.
convert to feet
find volume of two spheres with those diameters. subtract the two = volume of the steel of the big sphere
multiply by density of steel = weight of big steel sphere
3. WATER:
the total fillable space for the water to go would be the inside of the big hollow sphere (aka the volume as found by using the calculated inner diameter in part 2) minus the amount taken up by those 50 little spheres (aka the vol found in part 1)
then multiply by density of water = weight of total water
4. SUM
add up all 3 weights found. voila!
