I got 1545 (assuming its ok to post now that it's almost over). I was a little late being that I didn't have computer access most of the week (again). Anyways...
I took the surface area x the .08 for the outer steel then added that to the volume of a little steel ball (x50) for the total volume of the steel than multiplied by the 490. I then took the volume of the large sphere (assuming diameter was the 41, forgot to include the .08 for the volume) and subtracted the volume of the small spheres. This was my volume for the water which was then multiplied by the 62.4. I then added those 2 totals and rounded and got 1545.
I've been out of school a number of years and have had a hard time with these math ones (even googling the formulas). I was really good in math in hs, but as they say you don't use it, you lose it.... I can only assume I went about this the right way.
I hope tomorow's isn 't another math one -- i'll cry