NeoPets Riddles (Lenny Conundrums) and Answers Here

Then the frosting n top of each layer. Is it under the top two layers? Or is the cake frosted after construction, and there is no frosting under the top two layers?

Each tier was frosted on the top and sides

theres no frosting between the layers or under them(2 layers of jam though)

I assumed since they didn't specifically say that there was frosting under the top two layers, then there isn't any. Because they specified everything else.

Um, I came up with an answer, but I dont know if its right because when I was calculating the surface area for the frosting, I didnt take into consideration the additional 1.5 inches of jam between the 2 layers. Shoot. Thats an additional 3" per tier.

I mean 1/2 " of difference with the jam. Not 3" per tier. 1/2" additional per tier. **rolls eyes at herself**

I checked my work over several times. That was one of the things I missed the first time around. xD
What did you get as your answer?
I got 4220 when I rounded it. (:

I also got 4220 rounded. I'm gonna go check over it again though.

There is only 1 layer of jam per tier

No, there's two.
One between each layer of each tier.

I'm nowhere close to 4220.

After reading it, I think we have 9 layers of cake (each 1.5 inches thick) and 6 layers of jam (each 1/4 inch thick). I also calculated with 3 layers of frosting and 3 cylinders of frosting.

The layers of cake and jam have diameter 2/3" less than 12, 10.5 and 9, so I used 11 1/3, 10 5/6 and 8 1/3 as my diameters.

For the frosting, I used layers of diameter 12, 10.5 and 9, thickness 1/3". I also did 3 cylinders for the sides. To find the areas of the cylinders, I took the areas of the layers and subtracted the area of a layer of cake within the tier. I took the height of each cylinder as 5 inches - 3 x 1.5 + 2 x .25 (3 cake layers and 2 jam layers).

"The layers of cake and jam have diameter 2/3" less than 12, 10.5 and 9, so I used 11 1/3, 10 5/6 and 8 1/3 as my diameters."

No, the layers of cake are 12, 10.5, and 9. You have to add the icing onto that.
I think... Hope. o.o;

2(pi r 2) + (2 pi r)* h

I used that formula for calculating the surface area for the frosting but since I figured we werent frosting the bottom of each layer, I used (pi r 2) + (2 pi r)* h instead.

I just forgot to add the jam layer into the height.

And I messed up by multiplying the surface area x.33 for the frosting. Im pretty sure that was wrong. Im thinking I should have multiplied by 1.33. I dont know though. Its been YEARS since my last math class. lol

I thought you DID frost the top of each layer.

"Each tier was frosted on the top and sides"

Yeah, you frost the top, but not the bottom.

Okay, just clarifying. (:

Thats why you dont want to multiply by 2 since we only want frosting on 1 end of the cylinder, right?

I didn't multiply by two, I did every part of the cake separately and drew it all on a piece of paper. It was unfolded and it took forever. Dx
Hooray, drafting class.

Heh, thats how I did it too. It always helps me to draw math problems out on paper. lol

How did you figure out the frosting part? What did you multiply the surface area by to get the cubic inches of frosting? I totally screwed that part up.

i got something up around 44,000