A Chomby was walking down a path one day when Jhudora appeared in front of it. "Solve this puzzle, and you may pass," she said.
Suppose you have a very long steel bar, with a regular pentagonal cross-section where each side of the pentagon is 2 cm in length. This bar will be suspended vertically over a very deep chasm. At the bottom end of the steel bar, there is a spherical steel weight with a diameter of 50 cm. Going up the bar, at every 3 metre increment, there is a spherical steel weight with a diameter of 30cm.
If the density of the steel is exactly 7.8 g/cm3, the steel can withstand a tensile stress of 400 MPa, and gravity is 9.81m/s2, what is the maximum possible length, in metres, that the bar can extend without breaking? Round down to the nearest metre, submit only a number (with no additional or extraneous information), and disregard any deformation of the bar or any other forces acting on the bar.
Hey, I am new here. I have solved many LC's and gotten gold, so hopefully I can help
Math problems usually get me though..
Tensile stress (or Tss) and tensile strain (Tsa)I think needs be applied here. I was hoping it would be a quickie. But doesn't look that way. I have to run out. Be back in a few (if we still need help)
Xemnas wrote:Hey, I am new here. I have solved many LC's and gotten gold, so hopefully I can help
Math problems usually get me though..
welcome and can you help us on the current one. i dont know what to do
Lenny Conundrum
If I was that Chomby, I'd just turn around and walk home!
By the way, I just signed up. I just found this place last week, and I won the Lenny Conundrum! Unfortunately, I wasn't in the top 250.
Re: Lenny Conundrum
musicalsarah wrote:If I was that Chomby, I'd just turn around and walk home!
you got that right and jhudora for the third time? its getting old lol
MPa is MegaPascal 1 x 10^6 Pa
So, does anyone have a clue? I'm only in Algebra 1, and I skipped a grade!
I guess no one knows.. or they're keeping their mouth shut so the prize is bigger.
That's not a bad idea, though.
Be patient. We don't like when people come here begging for an answer. People are likely still researching and determining how to do the calculations, why not research it a bit yourself or go get a snack and come back later. There's no sense in waiting here begging for someone to just up and give you the final number.
Hello? Anyone here today?
stormygoddess wrote:Be patient. We don't like when people come here begging for an answer. People are likely still researching and determining how to do the calculations, why not research it a bit yourself or go get a snack and come back later. There's no sense in waiting here begging for someone to just up and give you the final number.
I'm sorry. I didn't want to make it seem like I was begging. I was just saying that some people like to keep the answer to themselves! That's actually very smart! Sorry if I made it seem like I was begging...
You're being horrifically impatient., Even YOU can see the problem is extremely complicated. and it JUST came out 10 minutes ago.
Come back in in a few hours, someone should have posted the method then, or some hints for solving.
Or DO THE WORK YOURSELF.
omg
yeah... Please do some research yourself. This is not an easy problem, and there is NO way that it will be solved less than 10 minutes after it came out... thanks...
Do the spheres count towards the length of the bar?
ro67 wrote:Do the spheres count towards the length of the bar?
That's a good question. I'd assume every section is 3m+30cm ...
I have the formula already. I will upload soon...
