NeoPets Riddles (Lenny Conundrums) and Answers Here

Quote:

Do the spheres count towards the length of the bar?

I would assume so...

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Do the spheres count towards the length of the bar?

No...that would affect the tensile and stress calculations. The sphere is just weight i would think.

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i found this...
its a bit extensive... but

http://chem.lapeer.org/PhysicsDocs/Goals2000/Lesson2.html

i have a better understanding of how this SHOULD work Razz

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ok. I posted the equations. Try to solve your own. I will clean up a bit when I have time. If you have any comments, post here or there Smile

http://lennyconundrumsolutions.blogspot.com/

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ok what grade are these questions?!? because i am only in high school!

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there stress equation could be in College. There rest should be in highschool. But you just have to plug in numbers and calculate.

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catfood wrote:

ok. I posted the equations. Try to solve your own. I will clean up a bit when I have time. If you have any comments, post here or there

http://lennyconundrumsolutions.blogspot.com/

t is the tensile stress right? and which do you use in the equation A = 5/4 t2 tan(54 degree)? 400 or 400,000,000. and sorry if i sound dumb, im not very good at math

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i was working it out on my own and got something insanely high...like..milions...im guessing that's wrong...

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ThezeR2HarD wrote:

catfood wrote:
ok. I posted the equations. Try to solve your own. I will clean up a bit when I have time. If you have any comments, post here or there

http://lennyconundrumsolutions.blogspot.com/

t is the tensile stress right? and which do you use in the equation A = 5/4 t2 tan(54 degree)? 400 or 400,000,000. and sorry if i sound dumb, im not very good at math

never mind i got confused but i get it now

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Im gonna get off now to go for dinner. I'm gonna clean up the equations a bit tonight with some references. Any comments will be responded.

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"The cross area can be calculated by the following equation:
A = 5/4 t2 tan(54 degree)"

I calculated 5/4 t2 but I don't get where tan(54 degree) comes in?

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Regular pentagon area

http://en.wikipedia.org/wiki/Pentagon#Regular_pentagons

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I used my own jumbled mess of logic and got a rod approximately 95537.6 meters long. Has anyone else gotten anyting close to this answer?

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polygon area calc...

http://www.mathopenref.com/polygonregulararea.html

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Catfood, i dont understand ... left side , right side.
why are there 2 sides

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there are always two sides to every equation...

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i have gotten to

Therefore, the mass that the steel bar can widthstand is:
m = F /g

where g = 9.81 m/s2 is the gravitational acceleration

and i have my M solved for. anyone else got this far? pm me Razz

)

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nevermind i can't pm i just found out Razz

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I found M...got lost at the 2nd formula x_X too jumbled for me to interpret lol xD.

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I'm so confused! I think I have been out of school for too long!

Roxie i am there too, only I have a feeling I have already messed up. Rolling Eyes

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NeoPets Riddles (Lenny Conundrums) and Answers Here

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