zappBrannigan wrote:Here are the general equations I'm using:
a(t) = a0 +a0't = 2t
v(t) = v0 + a0t + a0't^2/2 = t^2
x(t) = x0 + v0t + a0t/2 + a0't/3 = 2t^3/3
I'm not clear on how the apostrophe notation is working...?
For the interval 0
< t
< 15, we have:
. . . . .a(t) = 2t, with a(0) = 0
. . . . .v(t) = int [ a(t) ] dt = t^2 + c, with v(0) = 0
. . . . .v(0) = 0^2 + c = 0, so c = 0
. . . . .v(t) = t^2
. . . . .x(t) = int [ v(t) ] dt = (1/3) t^3 + d, with x(0) = 0
. . . . .x(0) = (1/3) 0^3 + d = 0, so d = 0
. . . . .x(t) = (1/3) t^3
I don't know how you got x(t) to be (2/3) t^3. Where did the "2" come from?
Note: Just as (2/3) is twice (1/3), so also 2250 is twice 1125. Your doubling came from that "2".
Eliz.