The LC authors, in Round 163, wrote:They started watching you the day before yesterday, when there were one-fifth the number of Meepits watching you today. Yesterday, eighteen more Meepits started watching you, but that was still only one-third of today's total. Tomorrow, there will be four times as many watching you as were watching you yesterday.
How many watchful Meepits will be added between today and tomorrow?
Let's label things:
. . . .number today: n
. . . .day before yesterday: (1/5)n = n/5
. . . .yesterday: n/5 + 18 = (1/3)n = n/3
Thus we have:
. . . .n/5 + 18 = n/3
Multiplying through by 15 to clear the fractions, we get:
. . . .3n + 270 = 5n
. . . .270 = 2n
. . . .135 = n
So there are 135 Meepits "today".
Since there were n/3 Meepits "yesterday", then there were 135/3 = 45 Meepits "yesterday".
Since "tomorrow" there will be four times the amount from "yesterday", then "tomorrow" will have 4(45) = 180 Meepits.
The difference between "today" and "tomorrow" is the number that will be added:
. . . .180 - 135 = 45
Just to clarify:
. . . .********************
. . . .****ROUND 163:*****
. . . .********************
. . . .***THE ANSWER IS***
. . . .********************
. . . .********"45"********
. . . .********************
Eliz.