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kemar
 
Reply Sun 24 Jan, 2016 10:53 am
2 particles of mass 0.2kg and 0.3kg are placed 0.15 meters apart. A third particle of mass 0.05kg is placed between them on the line joining the first two particles. Calculate:
A) The gravitational force acting on the third particle if it were placed 0.05 m from the 0.3...... I answered that one already the real problem that I am having is with question B.
B) Where along the line should it be placed for no gravitational force to be exerted on it. -----would really appreciate some help with this question
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fresco
 
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Reply Sun 24 Jan, 2016 11:29 am
@kemar,
B.
m1.m3/d^2 =m2.m3/(0.15 - d)^2

Solve for d
kemar
 
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Reply Sun 24 Jan, 2016 12:27 pm
@fresco,
Thanks!
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