Reply Sun 28 Sep, 2014 03:37 pm
Two blocks are hung by a string draped over a pulley, a 1.3-kg block on the left and a 3.4-kg block on the right. The two blocks start out at rest and at the same height.

part 1:
What is the change in the gravitational potential energy of the system of blocks and Earth when the 3.4-kg block has dropped 0.47m ? (Maybe this is important, but I just need the answer to part three)
answer is =-9.7J

part 2:
What is the change in the kinetic energy of the system between release and this instant? (Maybe this affects part three)
Answer to this part is 9.7J

part 3:
What is the velocity of the 1.3-kg block at this instant?
need answer
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Type: Question • Score: 0 • Views: 4,176 • Replies: 2
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mark noble
 
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Reply Wed 1 Oct, 2014 03:15 pm
The answer is simple - Spend more time learning and less time expecting others to do it for you.
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engineer
 
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Reply Wed 1 Oct, 2014 03:33 pm
@volleyballgurl48,
I have not checked your answers to 1 and 2 and will assume they are correct.

3) The change in potential energy has been converted to kinetic energy = 1/2 mv^2

so

9.7 J = .5 (4.7kg) v^2 and you solve for v.

Note that you use the total weight for the system.
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