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Need help with a logic problem

 
 
MPLC
 
Reply Fri 21 May, 2004 01:52 pm
Hi
I've been trying to beat a game for several days now, and it's driving me nuts!
You are up against the computer, all the spheres must be removed and the one who removes the last sphere is the loser.
first of al , a schematic:

O O O O O O
O O O O O
O O O O
O O O

these are spheres on a board.

These are the rules:

You can take any amount of spheres from a horizontal row during 1 turn.
You have to start.

It may seem simple, but it's actually really hard.
If anybody can figure out a sure-fire system, please let me know.
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Type: Discussion • Score: 1 • Views: 1,413 • Replies: 12
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MPLC
 
  1  
Reply Tue 25 May, 2004 04:09 pm
Well I figured it out on my own.
It appeared to be variation of an old game called "nim".
Solved it by using binary calculations.

Thanks a lot for who answered Confused
0 Replies
 
DrewDad
 
  1  
Reply Wed 26 May, 2004 02:31 pm
Can you post your solution?
0 Replies
 
stuh505
 
  1  
Reply Wed 26 May, 2004 05:42 pm
id rather you clarify the puzzle than spoil it by telling the solution Razz

you said you alternate taking spheres with the computer...and each turn you can take any amount of spheres in one row...but what does the computer take on it's turn? I should think this would be necessary to know in order to solve...
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MPLC
 
  1  
Reply Thu 27 May, 2004 05:10 am
stuh505 wrote:
id rather you clarify the puzzle than spoil it by telling the solution Razz

you said you alternate taking spheres with the computer...and each turn you can take any amount of spheres in one row...but what does the computer take on it's turn? I should think this would be necessary to know in order to solve...


The computer does exactly the same.
It takes way any number of spheres from a single row in order to make the player lose.

btw, There are only 4 starting moves which allow the player to win.
0 Replies
 
magnum
 
  1  
Reply Thu 27 May, 2004 05:35 am
the first row has 6 spheres in binary numbers:

110

you also write the other numbers in binary code

then you get a sum-->

110
101
010
011
-------
232 <---- this an uneven number wich you give victory
0 Replies
 
OCCOM BILL
 
  1  
Reply Thu 27 May, 2004 07:28 am
Is this a web based game you could post a link to?
0 Replies
 
MPLC
 
  1  
Reply Thu 27 May, 2004 07:32 am
Sure, here is the link: ww.ebaumsworld.com/pearl.shtml
0 Replies
 
whimsical
 
  1  
Reply Thu 27 May, 2004 09:01 am
What strategy most one follow in order to win?


whim
0 Replies
 
MPLC
 
  1  
Reply Thu 27 May, 2004 10:07 am
Do you want me to give you the solution?
0 Replies
 
whimsical
 
  1  
Reply Thu 27 May, 2004 03:50 pm
If you would.

whim
0 Replies
 
magnum
 
  1  
Reply Thu 27 May, 2004 06:44 pm
i gave you a hint, if it isn't clear you must say it !!!
0 Replies
 
whimsical
 
  1  
Reply Sun 30 May, 2004 03:10 am
It isn't clear. Why else would I ask for the applied strategy?

Whim
0 Replies
 
 

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