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Drawing Riddle/Puzzle

Forums: Riddles
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Reply Thu 6 May, 2004 07:59 am
Hi, first time posting something, but I wanna check if anyone has the answer to my problem.

A friend gave me this puzzle, and says it is possible, but I am certain it's not.

Code:-------------------
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Now, draw this shape. (all edges are solid) Starting anywhere you wish, draw a continuous line through each edge on the shape, and not cross over any edge twice. Every solution I have drawn either misses one side or crosses one twice. :S

Someone prove me right Smile
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Type: Discussion • Score: 1 • Views: 1,498 • Replies: 7
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DrewDad
 
  1  
Reply Thu 6 May, 2004 12:35 pm
I'm afraid I need some clarification....

You mean draw that shape without lifting the pencil/pen/writing utensil from the paper, and without crossing a line you have drawn, or re-drawing any part of the shape?
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whimsical
 
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Reply Thu 6 May, 2004 02:56 pm
You are right it is impossible without resorting to tricks.

Whim
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DrewDad
 
  1  
Reply Fri 7 May, 2004 10:05 am
Assuming you wrote the instructions the same way you were given them, this does sound like a trick.

Step 1: Draw this shape. This is easily accomplished.

Step 2: Draw a line through each edge.... You can accomplish this by drawing a curved line.
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whimsical
 
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Reply Tue 11 May, 2004 06:26 am
http://www.creativepuzzels.nl/spel/speel1/images/oplos31b.gif



whim
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Jack of Hearts
 
  1  
Reply Wed 12 May, 2004 12:40 pm
Whimsical is on the right track.
Just think outside the box.
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whimsical
 
  1  
Reply Thu 13 May, 2004 05:14 am
The only way for this to be possible without resorting to tricks like to solution I posted above, is for allowing 3D, I think.

In a flat plane there is no way to traverse each edge if you have an uneven number of chambers.

(out of the box) If you know of a way, I sure would like to know.

Whim
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neitsnie
 
  1  
Reply Tue 25 May, 2004 08:18 pm
draw the picture on a much smaller scale, say 1/32 of an inch wide and then draw on line over the picture using a 1.3 lead, sorry for the use of standard measurements for anyone using metric
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