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Reply Wed 15 May, 2013 07:46 pm
A body of mass 50kg is lefted vertically at a height of 10m. And take gas 10m/s2
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Type: Question • Score: 0 • Views: 558 • Replies: 2
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raprap
 
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Reply Wed 15 May, 2013 11:08 pm
@Eric T Gee,
m=50kg
s=10m
a=10m/s^2

What do you want to know
Energy, Force?
Please state the question

Rap
tomr
 
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Reply Wed 15 May, 2013 11:33 pm
@raprap,
Probably either wants velocity or time.
If m= 50kg and s= 10m and a= 10 m/s then:
x = xo + vot + .5at^2 ->xo = 0, v0 = 0
t = [(2x)/a]^(1/2) = (2(10)/(10))^.5
v = vo + at = 0 + 10(2^.5) = 14.142 m/s.

By KE:
PE = mgh = 50(10)(10) = 5000 J.
PE = KE
5000 = (1/2)mv^2
v^2 = 200
v = 14.142 m/s
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