A Ball is thrown how much meter will rise from ground?

You need to specify the coefficient of restitution.

The ball reached an apex, then started downward hitting the ground at 82m/s. V = at, and a=9.8m/s^2, so V = 9.8t. Compute t.

The distance traveled from a stop under constant acceleration is d = a t^2/2. You know a and t from above. Compute d.

Is this part of a mulitpart question? If you know the initial velocity from throwing the ball and assume no friction acting on it the velocity will not be just downward.

Ah I see. Assuming no bounce we are looking for the max height.
http://www.codecogs.com/code/engineering/projectiles/frictionless.php

The ball was thrown at an angle, so presumably the 82m/s contains both a horizontal and vertical component.

My friends,
You are exactly right, yesterday i couldnt write to the whole question.
H=125m Vo=65m/s angel is 37

a) How many s, then drops down?
b) (X) ? meter
c) The vertical and horizontal component of velocity before it hits the ground, what happens?
d) What will be the maximum rise from ground?

a)I found t= 10.4sn ,
b)X=540.8meter,
c)I found Vy=39m/sn, Vx=-62.92m/s, and final velocity as a 82m/s
but question of d?
I don’t know how to solve it?
Thank you very much for your responses

1) Break Vo into its horizontal and vertical components.
2) Take the vertical component, and see how long it takes to decelerate to zero.
3) Solve for distance traveled. (It's the same as distance over time, but you start with a positive velocity, and you have a negative acceleration.)
4) Add to your starting height.

A Ball is thrown how much meter will rise from ground?

if a hen and a half, lay an egg and a half, in a day and a half

how many pancakes will it take to shingle the roof of a doghouse

I always waffle on the answer.