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Thu 11 Oct, 2012 03:08 am
40 teams are taking place in a knock-out competition in which there is no seeding. They all have rankings determined by previous performance. The pairings are decided by a completely random draw, e.g. all the team names are put in a hat and drawn by a neutral party. What are the chances of the 14 top-ranked teams not meeting any team ranked higher than 15th?
Thanks,
Mazza
@mazza47,
Is this for the first round only - with no byes?
@mazza47,
Assuming the above, I get 0.027.
@markr,
Of course that doesn't mean much by itself. It depends on how probable other draws are.
Here are the probabilities for N of the top 14 seeds to play each other:
0: 0.027364406
2: 0.177868636
4: 0.366854062
6: 0.305711718
8: 0.106999101
10: 0.014590787
12: 0.000607949
14: 3.34038E-06
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