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In a simple pendulum, the centripetal force stem from the object's own mass, right?

 
 
Reply Tue 25 Sep, 2012 12:19 pm
As in the link below, mgsinθ=Fcentripetal. So this centripetal force is NOT an extra force, it stems from the round object's own mass right?

http://www.pinkmonkey.com/studyguides/subjects/physics/chap7/image10.gif

Yes or no question. If no, where does it stem from?
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DrewDad
 
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Reply Tue 25 Sep, 2012 12:37 pm
@cicibebe,
No, it is not centripetal force at all.

mg is the force exerted by gravity.

mgsinθ and mgcosθ simply break up mg into component forces. One force is in the same direction as the string, and the other is perpendicular to the string.

The centripetal force in the diagram is τ.
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dalehileman
 
  0  
Reply Tue 25 Sep, 2012 01:49 pm
@cicibebe,
Quote:
So this centripetal force is NOT an extra force,
Cici shouldn't that be "centrifugal"
DrewDad
 
  1  
Reply Tue 25 Sep, 2012 01:51 pm
@dalehileman,
Centripetal is the force acting to keep the body on a curve.

"to seek the center"


Quote:
Centrifugal force (from Latin centrum, meaning "center", and fugere, meaning "to flee") is the apparent outward force that draws a rotating body away from the center of rotation. It is caused by the inertia of the body as the body's path is continually redirected. In Newtonian mechanics, the term centrifugal force is used to refer to one of two distinct concepts: an inertial force (also called a "fictitious" force) observed in a non-inertial reference frame, and a reaction force corresponding to a centripetal force.
dalehileman
 
  0  
Reply Wed 26 Sep, 2012 09:25 am
@DrewDad,
Thanks Dad for the def and yes, that's how I understand "centrifugal". But clearly I don't understand the OP since I can't see with the swing of a pendulum how there's any centripetal force, that is, directed at the pivot
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