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bingo

 
 
Reply Tue 24 Feb, 2004 07:03 pm
Some people were playing bingo. They used only 10 numbered balls. They had cards with 3 different numbers on them.

A boy had all three numbers right in the first three draws. What was de chance of this happening?



LL
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Type: Discussion • Score: 1 • Views: 872 • Replies: 7
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SealPoet
 
  1  
Reply Wed 25 Feb, 2004 05:32 am
1/((10*9*8)^3)

I think.
0 Replies
 
laura nav nedu
 
  1  
Reply Wed 25 Feb, 2004 06:01 am
No that's not right. Remember, after each ball draw there's one less ball to pick from, and also one less number on the card.

L
0 Replies
 
SealPoet
 
  1  
Reply Wed 25 Feb, 2004 07:08 am
That's the 10*9*8 part.

But that's what I get for typing before coffee...

I'm going to think this through. I've taken classes etc. But it's been years...

In the mean time, 'fes up! This is your homework isn't it?
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Fraser
 
  1  
Reply Fri 27 Feb, 2004 09:39 am
Sealpoet why have you put 10*9*8 to the power of 3, surely thats not necessary, i think you only need a tenth*a ninth*an eighth to make 1/720.

Would like to know your thinking on that one.
0 Replies
 
Fraser
 
  1  
Reply Fri 27 Feb, 2004 09:42 am
Ooops, hang on.
maybe its 6/720 which makes it 1/120.
0 Replies
 
SealPoet
 
  1  
Reply Fri 27 Feb, 2004 09:45 am
mis read the question. I thought he won in the first three draws, three times in a row.

3/10 * 2/9 * 1/8 = 6/720 = 1/120

times the number of boys playing... if you don't specfiy which boy wins.
0 Replies
 
laura nav nedu
 
  1  
Reply Fri 27 Feb, 2004 10:18 am
Fraser and sealPoet:

3/10 * 2/9 * 1/8 = 6/720 = 1/120 is correct.

L.
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