Aakriti
 
Reply Thu 10 May, 2012 07:26 pm
A stone is dropped from the height of 45m.What will be the distance covered by it during the last one second of motion?Take g=10m/s2
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raprap
 
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Reply Thu 10 May, 2012 08:44 pm
@Aakriti,
s=1/2at^2
s=45m
a=10 m/s^2
Rearange to solve for t
t=sqrt(2s/a)=sqrt(90m/10 m/s^2)=sqrt(9 s^2)=3 s
the stone falls for 3 seconds

at the end of one second s=1/2 10 m/s^2 (1 s)^2=5m
at the end of two seconds s=1/2 10 m/s^s (2 s)^2=20 m
at the end of three seconds , that's a given 45m

Rap


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