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mindbender

 
 
Reply Tue 25 Nov, 2003 05:54 pm
A particular pumpkin weighs 3/4 of a kilogram plus 3/4 of a pumpkin. How much does this pumpkin weigh?
Not a riddle but does it matter?
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Type: Discussion • Score: 1 • Views: 1,926 • Replies: 18
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Adrian
 
  1  
Reply Tue 25 Nov, 2003 06:09 pm
4 times 1/4 of a pumpkin. Or to put it another way, as much as 1 pumpkin.
HehHeh.
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seancarlin
 
  1  
Reply Tue 25 Nov, 2003 06:20 pm
sorry adrian not the answer i'm looking for. but a gallant effort
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Craven de Kere
 
  1  
Reply Tue 25 Nov, 2003 06:27 pm
There is not enough information for an answer. The "a pumpkin" is undefined.
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seancarlin
 
  1  
Reply Tue 25 Nov, 2003 06:33 pm
I'm honoured Craven to have your company, but the question is correct and it has an answer
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Adrian
 
  1  
Reply Tue 25 Nov, 2003 06:33 pm
If the word "particular" was removed then the answer would be 3kg but with that word there you create ambiguity as to whether the two pumpkins are the same weight. Still like my answer though.
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Craven de Kere
 
  1  
Reply Tue 25 Nov, 2003 06:37 pm
sean,

I'll wait for the answer to restate my case. ;-)
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seancarlin
 
  1  
Reply Tue 25 Nov, 2003 06:41 pm
Adrian, you are correct, since this pumpkin weighs 3/4 of a kilogram plus 3/4 of a pumpkin, then 1/4 of a pumpkin weighs 3/4 of a kilogram and a whole pumpkin must weigh 3 kilograms

what a player,well done
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midgekelly
 
  1  
Reply Tue 25 Nov, 2003 06:45 pm
Couldn't spoil that one for you, you might not have let me stay in a fortnights time
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Craven de Kere
 
  1  
Reply Tue 25 Nov, 2003 06:47 pm
Ok, again "a pumpkin" was not defined and could have weighed anything.

"A person weighs 100 pounds plus 1/2 the weight of another person."

150 pounds? NO. The other person was not defined and could have weighed 200 pounds.

Again, there was not enough information for an answer. "A pumpkin's" weight can vary.
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seancarlin
 
  1  
Reply Tue 25 Nov, 2003 06:54 pm
disagress craven though i see where you are coming from , its a bit like algebra, youre given a bit of information and the rest adds on from there.
no doubt you will correct me again
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Craven de Kere
 
  1  
Reply Tue 25 Nov, 2003 07:01 pm
But like in algebra, you can't make the assumption that two variables are equal.

x = 3/4 + 3/4y

And also like in algebra sometimes you can't solve for x.
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seancarlin
 
  1  
Reply Tue 25 Nov, 2003 07:17 pm
since this particular pumpkin weighs 3/4 of a kilogram plus 3/4 of a pumpkin then the 3/4 of a pumpkin is actually defined. So 1/4 of a pumpkin weighs 3/4 of a Kilogram therefore a whole pumpkin in this particular case must weigh 3 kilograms
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Craven de Kere
 
  1  
Reply Tue 25 Nov, 2003 07:23 pm
The riddle didn't say "this pumpkin" + "this pumpkin".

There is nothing to qualify the second pumpkin's weight. It says "A pumpkin".

But I shan't continue the merry-go-round. Believe what you will and if neccessary we'll have to just think differently.
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seancarlin
 
  1  
Reply Tue 25 Nov, 2003 07:47 pm
its all good fun though
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seancarlin
 
  1  
Reply Tue 25 Nov, 2003 07:48 pm
best wishes Sean
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HighNRG2003
 
  1  
Reply Wed 26 Nov, 2003 08:07 am
Craven DO NOT Give up, U are Correct!!!! Cool
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Craven de Kere
 
  1  
Reply Wed 26 Nov, 2003 08:19 am
Oh, I know that but convincing sean is not on my list of priorities.
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Dakota4x4
 
  1  
Reply Fri 28 Nov, 2003 09:06 pm
This was quite simple, I found one pumpkin that weighed 3/4 of a kilogram, then took another pumpkin, cut 1/4 off then set it on a scale (it was the only way I could determine how much to add) added that weight to the first pumpkin and came up with 17 pounds.(the second pumpkin was really big)
If on the other hand the problem had more information, such as the weight of the second pumpkin, then it would be easy to solve the problem, as there was just no way to tell how much weight we were dealing with.

Or it could have read, A particular pumpkin weighs 3/4 of a kilogram plus 3/4 of the pumpkin....
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