Mon 25 May, 2009 02:50 pm
Can anyone help me with this riddle?
0 0 0 = 6
1 1 1 = 6
2 2 2 = 6
3 3 3 = 6
4 4 4 = 6
5 5 5 = 6
6 6 6 = 6
7 7 7 = 6
8 8 8 = 6
9 9 9 = 6
You can insert everything but numbers, and you can't change everything. I'm pretty sure you can only insert on the left side of the equal-symbol.
Here are the ones i have been able to solve so far:
2+2+2=6
3*3-3=6
√(4*4) +√4 = 6
6+6-6=6
sqrt(9)*sqrt(9)-sqrt(9)=6
7 - 7/7 = 6
And som half-solved:
(5 squared + 5)/5 = 6
cube root (8 * 8) + cube root 8
Hope you can help
(0 cos + 0 cos + 0 cos )! = 6
(1 + 1 + 1 )!=6
5+ 5/5 =
5+ 1 = 6
8 - square root of (square root of [8+8]) = 6
8 - square root of (square root of 4) = 6
8 - square root of 4 = 6
8 - 2 = 6
anyone figured out 10
i think if u can put a decimal point between the one and zero then you can treat as a number one equation
so (1.0 + 1.0+ 1.0)!=6
@raprap,
(10squared)log + (10squared)log + (10squared)log =
100log+ 100log+ 100log=
2+ 2+2 = 6
(sqrt(9)*sqrt(9))-sqrt(9) = 6
((log 10)!+(log 10)!+(log 10)!)! = 6
where logs are to base 10
for the case of eleven, 11 11 11 = 6
1+1+1+1+1+1 = 6
@jnejne,
more directly:
sqrt(4)+sqrt(4)+sqrt(4)=6
The original riddle doesnt allow the addition of any numbers. Squaring something requires that you write a 2.
others have correctly answered 0's and 1's and 8's, but there is a more elegant solution to 8's which make it act just like the rest of the questions
It has already been answered this way: 8-sqrt(sqrt(8+8) = 6
But after figuring out the 0's and 1's (learning to use factorial), another way to answer the 8's is:
SQRT( 8+(8/8) )! = 6
SQRT( 9 )! = 6
3! = 6
3 x 2 x 1 = 6
@bsingin64,
This one is a more preferable answer for me.
@jnejne,
Here is all of them solved to stop inconvenience:
(0!+0!+0!)!=6 (0!=1)
(1+1+1)!=6
2+2+2=6
3*3-3=6
Sqrt4+Sqrt4+Sqrt4=6
5/5+5=6
6+6-6=6
7+(7/7)=6
[Sqrt{8+(8/8)}]!=6
Sqrt9*Sqrt9-Sqrt9=6
Hope that helps.
@jnejne,
(0!+0!+0!)!=6
(1+1+1)!=6
2+2+2=6
(3+3-3)!=6
sqrt 4+ sqrt 4 + sqrt 4=6
5/5+5=6
6+6-6=6
7-(7/7)=6
(sqrt (8/8+8))!=6
9-(sqrt(sqrt 9+ sqrt 9))=6
@solipsister,
for the math sake you can not use cube root. so when you have 8 8 8=6 the only whey to do it is sqr((8/8)+8)!)
Stumble It!
Tweet This
Bookmark on Delicious
Share on Facebook
Share on MySpace