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I am a six digit code, the last number is 8, odd and even numbers alternate,

 
 
Reply Thu 19 Feb, 2009 06:41 pm
the difference between adjacent numbers is always bigger than one, and the first two digits, (read as one number), as well as the two middle digits,(read as one number), are multiples of the last two digits (read as one number)
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Type: Question • Score: 0 • Views: 901 • Replies: 9
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epenthesis
 
  1  
Reply Thu 19 Feb, 2009 08:15 pm
@michael912,
723618
DrewDad
 
  2  
Reply Thu 19 Feb, 2009 09:37 pm
@epenthesis,
epenthesis wrote:

723618

That no workie. 2 & 3 are adjacent, and the difference is not greater than one.
0 Replies
 
DrewDad
 
  1  
Reply Thu 19 Feb, 2009 09:38 pm
725418
solipsister
 
  1  
Reply Fri 20 Feb, 2009 12:39 am
@DrewDad,
720918
DrewDad
 
  1  
Reply Fri 20 Feb, 2009 07:47 am
@solipsister,
Wouldn't 09 be a factor, not a multiple?
0 Replies
 
markr
 
  1  
Reply Fri 20 Feb, 2009 06:37 pm
725418 is wrong because 5 and 4 are adjacent.
720918 is wrong because 09 breaks the odd/even alternating pattern.
There are five solutions that satisfy all requirements:
181818
183618
361818
363618
903618 (the only solution with unique digits, although that wasn't a requirement)
markr
 
  1  
Reply Fri 20 Feb, 2009 07:43 pm
@markr,
Oops - I overlooked two more solutions:
383838
585858
0 Replies
 
DrewDad
 
  1  
Reply Fri 20 Feb, 2009 08:01 pm
@markr,
markr wrote:

725418 is wrong because 5 and 4 are adjacent.

Dammit!
0 Replies
 
ActuaryInTraining
 
  1  
Reply Sun 22 Feb, 2009 03:18 am
@michael912,
an even number is defined as any number 2n where n is an integer

0 is and integer and 2(0) = 0.. so I am going to say that 0 is even.

That being said, your code is

903618
0 Replies
 
 

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