Mon 29 Sep, 2008 07:06 pm
A car of mass M is travelling up a straight road inclined at angle b to the horizontal. The engine of the car is working at rate P. At an instant when the speed is v & the acceleration is f the resistance to the motion due to frictional forces is kMg,where k is a positive constant. Express P in terms of M,g,v,f,k & b.
@Lingqi,
By considering force components what I find is ,
( P / v ) - kMg - Mg sin b = Mf , whence P = Mv ( gk + g sinb + f )
Stumble It!
Tweet This
Bookmark on Delicious
Share on Facebook
Share on MySpace