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Mon 25 May, 2009 02:50 pm
Can anyone help me with this riddle?
0 0 0 = 6
1 1 1 = 6
2 2 2 = 6
3 3 3 = 6
4 4 4 = 6
5 5 5 = 6
6 6 6 = 6
7 7 7 = 6
8 8 8 = 6
9 9 9 = 6
You can insert everything but numbers, and you can't change everything. I'm pretty sure you can only insert on the left side of the equal-symbol.
Here are the ones i have been able to solve so far:
2+2+2=6
3*3-3=6
√(4*4) +√4 = 6
6+6-6=6
sqrt(9)*sqrt(9)-sqrt(9)=6
7 - 7/7 = 6
And som half-solved:
(5 squared + 5)/5 = 6
cube root (8 * 8) + cube root 8
Hope you can help
(0 cos + 0 cos + 0 cos )! = 6
(1 + 1 + 1 )!=6
5+ 5/5 =
5+ 1 = 6
8 - square root of (square root of [8+8]) = 6
8 - square root of (square root of 4) = 6
8 - square root of 4 = 6
8 - 2 = 6
anyone figured out 10
i think if u can put a decimal point between the one and zero then you can treat as a number one equation
so (1.0 + 1.0+ 1.0)!=6
(10squared)log + (10squared)log + (10squared)log =
100log+ 100log+ 100log=
2+ 2+2 = 6
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