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Fri 6 Jul, 2007 10:01 am
Please help me solve this riddle before i simply lose my mind!
"A farm owner needs 100 people consisting of men, women and children to work in his field. He has 100 dollars. Men are worth $5.00, Women are worth $1.00 and Children are worth $.05. How many men, women and children can he get to work in his field with his $100.00?"
seriously, i am losing sleep over this so plese help me!
you HAVE TO use men, women and children....
arggghhh!
1 man, 94 women, 20 children
1 man, 93 women, 40 children
...
2 men, 89 women, 20 children
2 men, 88 women, 40 children
...
You have to have at least 20 children, cost of women and children must add up to a multiple of five.
This is not a riddle but a math problem:
M+W+C=100
5xM+1xW+0.05xC=100
Then, solve!
Francis wrote:This is not a riddle but a math problem:
M+W+C=100
5xM+1xW+0.05xC=100
Then, solve!
Three variables, two equations...
Please help me solve this riddle before i simply lose...
drewdad, those all work except it doesn't total 100 people...that's where i'm getting stuck....i had it they way you did by doing 18 men, 9 women and 20 kids and i got it WRONG...so frustrating! thanks though!
Oops.
Missed on of the criteria.
Back in a sec....
19 men, one woman, 80 children.
drewdad you da man!
thanks so much...i can go on living a normal life now
Using Francis' equations:
5m + w + .05c=100
m+w+c=100
w=100-m-w
5m + (100-m-w) +.05c =100
4m -.95c = 0
4m = .95c
400m = 95c
80m = 19c
m/c = 19/80
The ratio of men to children has to be 19:80. The only possible solution under the conditions is 80 children, 19 men, one woman.
Adding up the costs: 80 children = 4, 19 men = 95, one woman = 1
95+1+4 = 100
Good, Drew! I had that too.
thanks again!
Thanks again!
190 1 MAN 1 WOMAN AND 187 KIDS
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