They won't let me in Waggery so here it is.

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The love of my life, a snooty woman who lives at the end of the cul de sac has agreed I can have my way with her if I can answer this question!

"How many twos in ten if there are five in seven?"

I need help.

With either problem!
Laughing

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Type: Discussion • Score: 1 • Views: 906 • Replies: 10

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32 POSTS IN TWO YEARS! Shocked

My, you've been busy...

:wink:

x

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I wouldn't bother zoof. Snooty women are dangerous and not all that much fun.

Seaside girls are what you want.

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Bollocks Spendi!

The real fun girls work for the government, didn't you know that?

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five two = VII
ten two = XII

5--in--7 VII
6--in--8
7--in--9
8--in--10 <----- eight twos in Ten???
9--in--11
10--in--12 XII

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You shouldn't have 'conditions' on a shag - nor should you have to think that hard!

IMHO

x

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Whimsical,

Find out the street name and claim your reward.

x

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smorgs wrote:

32 POSTS IN TWO YEARS!

My, you've been busy...

:wink:

x

That snooty woman is hard to pin down. Takes time. But I have probably 15,000 posts on other boards. That snooty Ms Jones from the end of the cul de sac moves around. Where do you think the TV series "The Fugitive" got the idea from?
Confused

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spendius wrote:

I wouldn't bother zoof. Snooty women are dangerous and not all that much fun.

Seaside girls are what you want.

I have heard that about Seaside girls being discussed in the clubhouse. The consensus is that they have voluptuous sculptural forms and can be gritty.
Smile

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whimsical wrote:

five two = VII
ten two = XII

5--in--7 VII
6--in--8
7--in--9
8--in--10 <----- eight twos in Ten???
9--in--11
10--in--12 XII

Eureka! I think you have got it. Well (you) not yet.
I will spring it on her. If you hear shrieks of wonder emanating from the end of the cul de sac it can only mean she agrees there are 8in 10.
Cool

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if 7 = VII, then V II, 5 2's
so if 10 = X, shouldnt there be 0 2's?

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They won't let me in Waggery so here it is.

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