Each row must contain some permutation of the numbers from 1 to r, where r is the length of that particular row, and each column must contain some permutation of the numbers from 1 to c, where c is the height of that particular column.
Well done Mark, was not that hard, was it? But now this is.
You have only nine numbers given. Both main diagonals need to get the numbers from 1 to 9. Aswell as the diagonals from e9 via a5 to e1 and de diagonal from e9 via i5 to e1.
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markr
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Tue 20 Jun, 2006 01:21 am
This is tougher. I've got all the 7s placed.
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whimsical
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Fri 23 Jun, 2006 04:08 am
That's great... can you show me what you got?
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Vi
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Thu 29 Jun, 2006 07:48 am
I'm also stuck with only sevens. I've only made even one other little deduction, and that's that benign can't before.
Well, I had to resort to writing a program.
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