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Wed 25 Jan, 2006 10:29 pm
Ten boxes are arranged in the order as below.
8 - 6 - 2 - 5 - 10 - 1 - 3 - 7 - 9 - 4
You need to have them in their correct order: 1, 2, 3, 4 and so on... The numbers you move have to go to the right end. You can move up to three adjacent boxes per move.
What's the fewest amount of moves to do this?
How! War Eagle, welcome to the forum. I come in peace when I say I can do the task in five moves. If anyone can beat that, they speak with forked tongue.
Can you verify what you did?
I think it's . . .
8 - 6 - 2 - 5 - 10 - 1 - 3 - 7 - 9 - 4
8 - 6 - 2 - 3 - 7 - 9 - 4 - 5 - 10 - 1
8 - 6 - 7 - 9 - 4 - 5 - 10 - 1 - 2 - 3
8 - 6 - 7 - 9 - 10 - 1 - 2 - 3 - 4 - 5
8 - 9 - 10 - 1 - 2 - 3 - 4 - 5 - 6 - 7
1 - 2 - 3 - 4 - 5 - 6 - 7 - 8 - 9 - 10
Is this true? Is it possible to have less? Thanks for replying Tryagain. I appreciate it.
Congratulations!
"Is this true?"
You better believe it.
"Is it possible to have less?"
Not this side of the burnt stump.
"Thanks for replying Tryagain. I appreciate it."
No probs. It was foretold in riddle folklore when it was written; from the west shall come one that is a high flier.
I can't get ther in less than 7 moves
s)8625013794
1)8623794501
2)8694501237
3)4501237869
4)0123786945
5)0123789456
6)0123456789
7)1234567890
Rap
Rap
Dammit that works in 5
Rap
Black stump Try BLACK STUMP not burnt shheeeeshhh its not that hard.
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