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Hotel Riddle.....

 
 
Reply Tue 15 Nov, 2005 01:00 pm
Good luck on this one.... read the whole riddle and try to figure it out...

Three men go to a cheap motel, and the desk clerk charges them a sum of $30.00 for the night. The three of them split the cost ten dollars each. Later the manager comes over and tells the desk clerk that he overcharged the men, since the actual cost should have been $25.00. The manager gives the bellboy $5.00 and tells him to give it to the men. The bellboy, however, decides to cheat the men and pockets $2.00, giving each of the men only one dollar.

Now each man has paid $9.00 to stay for the night, and 3 x $9.00 = $27.00. The bellboy has pocketed $2.00. But $27.00 + $2.00 = $29.00. Where is the missing $1.00? WTF?
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Type: Discussion • Score: 1 • Views: 1,036 • Replies: 3
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carditel
 
  1  
Reply Tue 15 Nov, 2005 04:41 pm
Answered many times:- the $27.00 includes the $2.00 , the extra $3.00 is the $1.00 each of the men have returned to them.
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bluberri creme
 
  1  
Reply Sat 21 Jan, 2006 11:09 pm
The men each paid $10, remember? Split 30 into 3 is ten. The bellboy keeps two of the 5 dollars and give each man one dollar back.
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Chai
 
  1  
Reply Sat 21 Jan, 2006 11:17 pm
carditel correct bluberri.....

you're looking at it the wrong way, which of course is what the riddle wants you to do.....

the men paid 30.

the bellhop kept 2........30 minus 2 = 28

28 minus the 3 he gave back is 25.....the cost of the room.
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