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3 guys, 5 dollars, and a hotel room

 
 
Reply Tue 25 Oct, 2005 12:58 am
3 guys each have 5 dollars. They go into a hotel room and consequently 1 room costs 15 dollars. They pool in all their money and buy 1 room. The lady at the desk felt sorry for them, because it was the only money they had. So, she decides to give them a discount and knock off 5 dollars. Finally, she gives the 5 dollars to the bellboy to give back to the three guys. The 3 guys were so happy that they decided to give the bellboy a 2 dollar tip, and split up the rest of the money. So, the bellboy got 2 dollars, while each of the guys get 1 dollar - it adds up to 5 dollars.

Essentially each guy paid 4 dollars (they all paid 5 dollars, then got 1 back from the bellboy). Now, 4 dollars multiplied by 3(number of guys) is 12 dollars, and add that to the 2 dollars the bellboy has, thats 14 dollars

What happened to the other dollar?
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Intrepid
 
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Reply Tue 25 Oct, 2005 01:27 am
The room cost $10.00 + $2.00 for the bellboy = $12.00 + $3.00 ($1.00 each from the 3 men) = $15.00
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phoenix 01
 
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Reply Wed 26 Oct, 2005 03:56 pm
Re: 3 guys, 5 dollars, and a hotel room
jughead44662 wrote:
Essentially each guy paid 4 dollars (they all paid 5 dollars, then got 1 back from the bellboy). Now, 4 dollars multiplied by 3(number of guys) is 12 dollars, and add that to the 2 dollars the bellboy has, thats 14 dollars

What happened to the other dollar?


The $4 multiplied by 3 number, includes the bellboy's tip. $12= cost of room ($10) plus bellboy's tip ($2). Instead of adding the bellboy's tip at the end, you should add the total dollars the guys have left.

The correct way to calculate the total is:

$4*3=$12 (cost of room including tip) + $3 (money guy's have left)= $15

What the riddle calculates is:

$4*3=12 (cost of room with tip) + $2 (cost of tip) = $14

The riddle incorrectly counts the tip twice. The "missing" dollar is the difference from $3 (money guy's have left) - $2 (cost of tip).
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