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Thu 15 Sep, 2005 03:39 am
A person has to cover the fixed distance through his horses. There are five horses in the cart. They ran at the full potential for the 24 hours continuously at constant speed and then two of the horses ran away to some other direction. So he reached the destination 48 hours behind the schedule. If the five horses would have run 50 miles more, then the person would have been only 24 hours late. Find the distance of the destination.
I get 1000/3 (333.333333...) miles.
You can think it like ..
You can thinl like, the speed became 3/5th after the man lost his horses...
You don't like my answer?
Actually, the speed became 3/5 of the original speed after he lost his horses.
Ya u r right, but ur answer is not,
Suppose his actual speed is 'v' with 5 horses,
If he travelled that 50 miles with 5 horses the time taken wud b 50/v, which equals time taken with 3/5th speed minus 24hrs
50/v = 50/(3v/5) - 24;
so, v = 25/18;
Now, suppose after 1st 24 hrs he takes 't' hrs toreach his destination, then
vt = (3v/5)(t + 48);
t = 24;
that meens, total time taken with 5 horses wud be 24+24=48hrs
thus distance is,
vt = (25/18) * 48;
= 200/3
not 1000/3;
I see my mistake (I didn't account for the time it took for the horses to go the 50 miles).
I also see your mistake.
vt = (3v/5)(t+48)
t = 72
total time = 72+24 = 96
distance = 400/3
Oh yes you are right,
My mistake sorry....
ya.. the answer is 400/3
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