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Sun 13 Feb, 2005 03:20 am
Puzzle deleted.
Condition 4 can be restated as:
For each two sheep, there is precisely one wolf that has bitten both sheep.
If S1 and S2 were both bitten by W1 and W2, then condition 3 would be violated.
Little Bow Peep has lost some sheep. Good point Mark, the impossible problem. I think a slight change of wording is necessary. Good effort Whim, keep up the good work.
Whim,
So conditions 3 and 4 no longer apply to all pairs of wolves and sheep respectively?
Do they each apply only to a single pair, or at least one pair?
edited. I was the worse for drink when I posted this. My apologies
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