Re: Can Anyone Solve This? I've Been Trying And I Still Can'
fringey218 wrote: There were five friends, Stephanie, Laura, Anna, Taylor, and Maggie. Laura's age was that of Taylor's plus Stephanie's ages. Maggie was twice Taylor's age, or the same age as Stephanie and Laura put together. Anna's age was three times the average of all five of their ages.
If Taylor is 4 months older than Stephanie, how many months old is Anna?
I added visuals because I find they help.
Recording the above statements in algebraic statements:
La = Ta + St
Ma = 2Ta
Ma= St + La
An = .6 (La + Ta +St +Ma + An)
Ta = St + 4 mo
Now, doing a few computations:
Ma = St + La = St + Ta + St = 2St + Ta = 3St + 4 mo = 2Ta = 2(St + 4 mo)
Rearranging this last, 3St + 4 mo = 2St + 8 mo
Subtracting 2St from both sides:
St + 4 mo = 8 mo
St = 4 mo
Ta = St + 4 mo = 8 mo
Ma = 2Ta = 16 mo
La = Ta + St = 12 mo
An = .6(12 mo + 8 mo + 4 mo + 16 Mo + An)
.4 An = .6(40 mo) = 24 mo
An = 60 mo
Stumble It!
Tweet This
Bookmark on Delicious
Share on Facebook
Share on MySpace