LC is postpone til next week...guess less than 250 people answered this weeks challenge...I think I will get the avvie this time...
how are you sure it's postponed? it's still a little early to get the "congrats" neomail. i've seen them come out much later.
but if it IS postponed, they might be coming up with a whopper for the next one (and most likely last of the year.) perhaps LennyFan is right, and it will be something where you have to go through all of the news postings, and they need some time to check the answer themselves =P
just got my "congrats" neomail. only 545NP this week. seems lot's of people got it right.
and there should be a new one today.
@jjbuttcrack,
Somewhere between 3670 and 3676 correct responses. Guess lots of people know some math. LC isn't closed yet, so I won't put out the solution right now.
I was fast on this one, and got an upgrade.
I might not be around when tonight's puzzle appears, though. For some reason, I think tonight's puzzle will have something to do with certain squiggly creatures.
@Kutusita,
Interesting theory - to me, that seems like a minor enough part of the site that I tend to doubt the LC will be related.
Okay, time for the solution:
The key is to work backwards. We know the final number of grams of omelette left and we know what percentage each Neopet ate.
If we start with a certain number of grams, call it A, and the Neopet eats P% of the omelette, then we have B = A - A * (P/100) grams left after the Neopet eats. (P/100 gives us a decimal value for the percent and we take the original amount, minus what the Neopet ate.)
This becomes B = A * (1 - P/100) and can be rearranged to A = B / (1 - P/100).
Our final amount is 878912 grams.
Before the Jetsam ate 7.5%, there were 878912 / (1 - .075) = 950175.1351 grams. (I'm rounding to 10 significant digits at all steps.)
Before the Buzz ate 1.2%, there were 950175.1351 / (1 - .012) = 961715.7238 grams.
Before the Kacheek ate 3.6%, there were 961715.7238 / (1 - .036) = 997630.4189 grams.
Before the Elephante ate 10.3%, there were 997630.4189 / (1 - .103) = 1112185.528 grams.
Before the Lupe ate 6.2%, there were 1112185.528 / (1 - .062) = 1185698.857 grams.
Before the Eyrie ate 5.0%, there were 1185698.857 / (1 - .050) = 1248104.061 grams.
Before the Grarrl ate 9.1%, there were 1248104.061 / (1 - .091) = 1373051.772 grams.
Before the Kau ate 4.3%, there were 1373051.772 / (1 - .043) = 1434745.843 grams.
Before the Grundo ate 3.5%, there were 1434745.843 / (1 - .035) = 1486783.257 grams.
Before the Scorchio ate 4.7%, there were 1486783.257 / (1 - .047) = 1560108.349 grams.
Before the Moehog ate 5.0%, there were 1560108.349 / (1 - .050) = 1642219.315 grams.
Before the Skeith ate 8.2%, there were 1642219.315 / (1 - .082) = 1788909.929 grams. (This calculation is actually unnecessary since we only care about what the Moehog ate.)
Now we want how many grams the Moehog ate, so we take the amount before the Moehog ate and subtract how much there was after it ate to get 1642219.315 - 1560108.349 = 82110.966, which rounds to 82111 grams. Alternatively, take 5% of 1642219.315 to get 82110.96576, again rounding to 82111 grams.
ahhh i'm so excited!! hopefully only a few more minutes now...
THIS WEEKS PUZZLE - ends Next Wednesday, most likely
Balthazar was walking down a path one day when a Spardel appeared in front of him. "Solve this puzzle, and you may pass," the Spardel said.
________ SHCR GKCSDH WTFPBBHM BPABFC KHGMHG RMOHCMCT CNSCS SNBKRIAB TCQT DNCTDNO FWSNL DRDCT CSPACB HOKHB _______ HMISHFT SDMSDS _________
What do you get when you take the three missing words, put them together, and rearrange the letters in alphabetical order? For example, if the three words were "HSGA", "UUAM", and "PYTQ", you would submit the answer "AAGHMPQSTUUY". Submit ONLY the word with no other information, or your answer will be marked as incorrect!
Wow, no short words - smallest one is 4 letters.
when I highlight the underlined portion (i guess the missing words) on the official lenny page, there are 8, 7, and 9 underscores respectively
@vvktv,
I get the same thing in the source code. Not sure it means anything, but something to keep in mind.
top most appearing letters:
C (12)
S (11)
H (10)
B (8)
least:
L, Q (1)
I, W (2)
A, G, O, P (3)
Just passed it trough a caesar cipher(switch all letters a certain number) decrypter -13 to 13 and nothing.
We've had a fair number of letter pairing problems - each pair gives you the letter that is halfway between.
But the 5 and 7 letter words make that less likely. Based on the statement of the puzzle, it seems likely that each apparent word is an actual word of some sort.
Well some words have an odd number of letters
