605
   

NeoPets Riddles (Lenny Conundrums) and Answers Here

 
 
jcrboy
 
  1  
Reply Wed 2 Sep, 2009 07:27 pm
@jcrboy,
29808 does indeed seem to be the right answer
0 Replies
 
krazykatana
 
  1  
Reply Wed 2 Sep, 2009 07:35 pm
btw the only difference is that I used inner+1,25 to get the middle circle, than I just find lenght than multiply by 2.5*25*7.85

you do outer minus inner, so yeah pretty much the same thing all in all, I think the interpretation of a square shaped tube forming the hoop is the right one.
0 Replies
 
spaceymom
 
  1  
Reply Wed 2 Sep, 2009 09:44 pm
I came to the same conclusion. I have another question. Does anyone remember what the prize was for #320? I was on vacation and missed it and I wanted to put it in my list.
0 Replies
 
skatepunk753951
 
  1  
Reply Wed 2 Sep, 2009 11:23 pm
So I don't understand why you are looking at inner circles and outer circles?

Here's how I interpreted the question:
Imagine you cut the hoop and flattened it out. You would have a long cylinder the length of the circumference of the loop (much like when you cut the edge of a cylinder and unroll it, which creates a rectangle.) I believe the other two dimensions of this cylinder are what the "square cross section" is referring to, meaning the unraveled hoop is really more of a rectangular prism, with two sizes that are 2.5 cm and the third is the length of the circumference of the circle.

Therefore, Volume of the hoop = 2.5 x 2.5 x C
So, V = 2.5 x 2.5 x pi x radius
Then, obviously with volume and density finding the mass is easy.

So all you need is the radius, which is where I'm stumped.

However, using the radius jcrboy found (5785/64) I get the same answer krazykatana said he and willzi got. (27865 with full pi, 27850 with 3.14)
anonymous-npt
 
  1  
Reply Wed 2 Sep, 2009 11:47 pm
You can't just unroll the hoop into a rectangular prism because the two sides are different lengths. You have to take into account the radius to the inside of the hoop and the radius to the outside of the hoop. Just do big circle area - little circle area = hoop area; multiply by height to get volume, multiply by density to get weight. 29808 (more precisely, 29808.02347 but obviously we round to to the nearest gram.)
0 Replies
 
felineforever
 
  1  
Reply Thu 3 Sep, 2009 10:23 am
ahh this is so confusing! Sad
0 Replies
 
krazykatana
 
  1  
Reply Fri 4 Sep, 2009 05:36 pm
@skatepunk753951,
The radius is exactly where you need to look at inner and outer, also the 5785/64 was wrong as it was made assuming the distance between the bottom shelf and the hoop was 32, which is isn't, 32 is the distance shelf to shelf not shelf to hoop.

The radius is actually just triangles, we make a line from an end of the bottom shelf to the center of the circle, than take half the shelf for another line than the last line of the triangle is from the middle of the shelf to the center of the circle. Use the radius as a variable to find the lenght of all sides , use pythagorean theorem than solve the equation and you get your radius.
krazykatana
 
  1  
Reply Fri 4 Sep, 2009 05:49 pm
@krazykatana,
btw your interpretation is pretty much the same as ours, cept that we don't... explain it the same way, we simply say the tube forming the hoop has a square form. From that you can deduce that if "unlooped" it would make a rectangular prism with dimensions lenghtx2.5x2.5 . Basically what you say is what we said we just ... don't verbalize it as much.
0 Replies
 
krazykatana
 
  1  
Reply Fri 4 Sep, 2009 06:07 pm
o and if it is jcr's way to solve the problem that leaves you puzzled, it is because he found the dimensions of the loop in a different way, basically he saw the hoop as a disk from wich has been removed another smaller disc, so what he did was to "remove" the "inner disk" from the "outer disk", leaving the hoop.

thats the kind of strategy we use more often with calculus but still applies to regular geometry.
0 Replies
 
mellsie
 
  1  
Reply Wed 9 Sep, 2009 04:17 pm
WT AQ NU JN RD CM DP OQ AT IW DJ VK NT FM JG NA YV OA FD GO YD XN CX JL TA WX HI AC AV GH JY NQ UD KF TA VZ OM MA UX CD AP IA NP DI PB DZ MD VV AA LC DA VU AW YU FT AJ LA DO MP SB BI NE IA IB TO IT DR RO NF DG UW FD GM FY IZ WZ SL JB GR RD QI RA AQ LF WC FJ ZT UP SO HW

What is the answer? Do not submit any extra information.
0 Replies
 
jjbuttcrack
 
  1  
Reply Wed 9 Sep, 2009 04:25 pm
hmmm... i have no ideas yet
all i know is that the method used for the last one that looked like this (assign them number, add the pair, and divide by 2 to decode the letter) doesn't work here. =/
starleogirl09
 
  1  
Reply Wed 9 Sep, 2009 04:39 pm
@jjbuttcrack,
Yeah, I tried using the method but it didn't work.
0 Replies
 
jjbuttcrack
 
  1  
Reply Wed 9 Sep, 2009 04:42 pm
yeah -- the first letter gives you something odd, so dividing by 2 won't work.

i thought about shifting the numbers (like, starting with C=1) -- but even that will give you an odd answer for the first letter.
0 Replies
 
Firestar624
 
  1  
Reply Wed 9 Sep, 2009 04:43 pm
I tried doing letter opposites like A=Z, B=Y, and so on but it doesn't seem to fit.
0 Replies
 
jcrboy
 
  1  
Reply Wed 9 Sep, 2009 04:50 pm
Obviously not based on keyboard layout... so I'm trying out some other methodologies myself... this one might take some significant trial and error to get ><
jjbuttcrack
 
  1  
Reply Wed 9 Sep, 2009 04:54 pm
wow -- i'm coming up with nothing.

i think the first letter-pair has to somehow decode to a 'w' because these things are always a question, and most of the question words start with 'w' (where, why, who, what, when) -- but by the same logic is could also be 'h' for 'how' ...
0 Replies
 
starleogirl09
 
  1  
Reply Wed 9 Sep, 2009 04:54 pm
@jcrboy,
Some of them look like abbreviations and some are words...maybe we need to move the letter pairs around to build the question
dawnmomoffour
 
  1  
Reply Wed 9 Sep, 2009 05:00 pm
@starleogirl09,
LOL If you start at the end and read backwards..first two words say "Whos put" but then it is gibberish. Most progress I've made so far LOL
dawnmomoffour
 
  1  
Reply Wed 9 Sep, 2009 05:06 pm
@dawnmomoffour,
Also tried using the telephone for letters..couldn't get anywhere there either.
starleogirl09
 
  1  
Reply Wed 9 Sep, 2009 05:12 pm
@dawnmomoffour,
All I saw in there was HI AC :-P
I counted that there are 90 letter pairs, so that's 180 total letters.

Other than that, I have no idea.
0 Replies
 
 

Related Topics

Lenny Conundrum 464 - Question by jreneearias
Lenny Conundrum #463 - Discussion by barkie
Lenny Conundrum (wed) DECEMBER 8 2010 - Question by Joanneexoxo
answers - Question by qftcu1
Lenny Conundrum 354 - Discussion by hippiegirl101
lenny conundrum 4/16 - Question by punkd4life3
 
Copyright © 2025 MadLab, LLC :: Terms of Service :: Privacy Policy :: Page generated in 0.1 seconds on 01/11/2025 at 08:53:19