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NeoPets Riddles (Lenny Conundrums) and Answers Here

 
 
bluepanther2
 
  1  
Reply Wed 27 May, 2009 06:39 pm
@Lameme,
That's only the corridor. If from the center of each intersection it's 25 m, and the intersection is a square (3 x 3), then only the corridor would be 25 - 1,5 - 1,5 = 22.
B55B55
 
  1  
Reply Wed 27 May, 2009 06:41 pm
@eilonwy42,
Well I definitely could have made a mistake.
I had corridor volumes of 225 (3*3*25)
And intersection volumes of 27 (3*3*3)

Do we at least agree on that part? (Read: Did I make a basic math mistake)
eilonwy42
 
  1  
Reply Wed 27 May, 2009 06:43 pm
@bluepanther2,
Aren't there a few corridors that would only have 1 end chopped off? In that case I would get 1***9
0 Replies
 
eilonwy42
 
  1  
Reply Wed 27 May, 2009 06:45 pm
@B55B55,
The problem I've found with this is that it doesn't take into account that it is 25 meters to the CENTER of the intersection. You have to chop off 1.5 meters on each end, other than the ones that only have an intersection on one end. Does that make sense?
eilonwy42
 
  1  
Reply Wed 27 May, 2009 06:49 pm
I've submitted my 1***9, but I could be wrong. I'm willing to help working on it.
0 Replies
 
B55B55
 
  1  
Reply Wed 27 May, 2009 06:50 pm
@eilonwy42,
When I used a 25 meter passageway I removed the volume of overlapping 4 way intersections.
Mathematically I got the same results with this as with 22 meter passageways (Volume 198) and adding in the volume of 4,2 and 1 way intersections.
Lameme
 
  1  
Reply Wed 27 May, 2009 06:52 pm
@B55B55,
I never used 22m for the corridors, it will never be the same number. You separated the corridors in categories while I used only 25m :S

Because it said: Assume that 25 metres is the exact distance between the centres of each intersection.

0 Replies
 
edstock
 
  1  
Reply Wed 27 May, 2009 06:52 pm
@B55B55,
B55B55 wrote:
I drew mine out on graph paper and also got a diamond.

I found that the first step had 4 passageways, (obviously) but then the second step had 12 new passageways as 4 of it's potential passageways were the original. I ended up with sixty something total passageways.

I think the tricky part is the existence of two passageway intersections.
When 4 passageways intersect you have to remove the area of 1 intersection. (If two passageways connect in a straight line, the intersection makes that equal to two passageways. Having another set on top means a loss of the size of one intersection). I ended up with 20 something of those.

However when two passageways intersect at a right angle they either don't lose any space at all, or they lose 1/4 of an intersection. (as they have 1/4 overlap and 1/4 of the space is not tunneled out)

My assumption is that the intersection of any two paths is squared out the way that it would be. That would mean that a two passageway intersection can be ignored. (I found there to be 12 of these though)


This looks like what I've drawn out. I get 25 4-way intersections, 12 2-way intersections, and 4 dead-ends/cul-de-sacs, with 64 passageway sections.

As B55B55 said, the questions come out at the 2-way intersections, and I would also say, at the dead ends. Both the 2-way intersections and the dead-ends come at the last step, where the LC says "with passages going 25 metres in each direction." Then it says, "each intersection is a 3-metre by 3-metre square." So the question is whether the 2-way intersections are intersections for purposes of the second quote, or whether the passages just go the 25 metres and leave the 1/4 intersection closed off. Looking at "Assume that 25 metres is the exact distance between the centres of each intersection," I would also wonder if the dead-ends hollow out the other halves of the terminal intersections, or whether they stop exactly at the 25 metre point.

If I hollow out both the 2-way and the dead-ends, I get 1***9. If I hollow out only the 2-ways, I get 1***5 and if I don't hollow out anything, I get 1***4.
eilonwy42
 
  0  
Reply Wed 27 May, 2009 06:53 pm
@B55B55,
Sounds like you understand it better than I do! What did you get?
0 Replies
 
eilonwy42
 
  1  
Reply Wed 27 May, 2009 06:55 pm
@edstock,
I got those three answers too...I went with 1***9
edstock
 
  1  
Reply Wed 27 May, 2009 06:56 pm
@eilonwy42,
I decided to go the other way and submitted the 1***4 answer for nothing hollowed out. It isn't clear to me which one they will choose.
0 Replies
 
bluepanther2
 
  1  
Reply Wed 27 May, 2009 07:00 pm
@edstock,
I re-did it and got these three results. (I got the 1***4 before). I decided to go with the 1***4, too.
0 Replies
 
jjbuttcrack
 
  1  
Reply Wed 27 May, 2009 07:01 pm
Lameme-- you are soooo on the right track. at least, your description is correct.

the part that you (and many others) are overlooking is that the length of the passageways given will give you an overlapping area. 25m from Center to Center of intersections. it is MUCH easier to account for this if you consider the figure in this way. Each intersection is a 3*3 'room'. the connections between these rooms are only 22m (because 1.5m is lost to the 'room' on each end.) just be careful about the ones that don't have a room at both ends and calculate them seperately.

i agree with the 1***5 answer. proved it to myself many ways. it is up to you whether you agree with me.
Lameme
 
  1  
Reply Wed 27 May, 2009 07:06 pm
@jjbuttcrack,
I think they gave the info about intersections (3*3) because we needed to know if it was different to the corridors and it is not. That's why I didn't use it. I can't tell if it is right or wrong to discard that information but if it says that in the end, and starting in the center of the last intersection, we go 25 m down, that means that the dead ends have the missing 1.5m completing the 25m that every passageway has (in my numbers).
Stumpt
 
  0  
Reply Wed 27 May, 2009 07:12 pm
@Lameme,
so is it 12345 or 12349
Lameme
 
  1  
Reply Wed 27 May, 2009 07:13 pm
@Stumpt,
I got something different.
0 Replies
 
edstock
 
  1  
Reply Wed 27 May, 2009 07:15 pm
@Stumpt,
Stumpt wrote:
so is it 12345 or 12349


Probably not either. Nobody has given their three middle digits. And we have uncertainty about how to handle the 2-way junctions and dead-ends.
Lameme
 
  1  
Reply Wed 27 May, 2009 07:29 pm
@edstock,
Yes, we have. We'll find it out next wednesday.
0 Replies
 
jjbuttcrack
 
  1  
Reply Wed 27 May, 2009 07:30 pm
@edstock,
well, at least to me, the wording of the given info (and the geometry once you've drawn it out), make it pretty clear how to handle the 2-way junctions and dead ends.

junctions ARE intersections and thus should be gtiven the full 3x3 room.
dead ends are NOT intersections (obviously!) and thus extend 25m from the center of their room.
0 Replies
 
Nooblette
 
  1  
Reply Wed 27 May, 2009 07:59 pm
omg...... my sister made a new pet and didn't go to that page for last weeks Lc =(

and this week i got 1***5

assuming that they end up with 3x3x3 at all the intersections....

or otherwise i'm wrong....

Aaaarrrrrgggghhhhh! it took me 2 weeks of not doing homework searching for pages....... and still failed.... Anyway how would anyone know what the name of the picture was?
 

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